Java实现单链表的反转

Java实现单链表的反转
方法一：遍历反转

class Node{ //构造方法
public int date; //0
public Node next; //null

public Node(int date){
    this.date=date;
    this.next=null;
}

}
public class link{
public Node reverse1(){
Node cur = this.head;
Node prev = null;
Node newHead = null;
while(cur != null){
Node curNext = cur.next; //备份后面的
if(curNext == null){
newHead = cur;
}
cur.next = prev; //反转第一个节点，将head.next先置为空；
//下一次反转时将前驱的节点给后面，造成反转效果
prev = cur; //后移
cur = curNext; //后移
}
return newHead;
}
}
方法二：头插法反转

public Node reverse2(){
Node temp = null;
Node cur = this.head;
if(cur == null || cur.next == null){
return head;
}
while(cur != null){
Node next = cur.next; //备份后面的
cur.next = temp.next; //1
temp.next = cur; //2
cur = next;
}
return temp.next;
}

文章转自：Java实现单链表的反转_Java-答学网

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