杭电oj2032、2040、2042、2054、2055

2032  杨辉三角

 1 #include 
 2 
 3 int main(){
 4     int s[31][31],i,j,n;
 5     while(~scanf("%d",&n)){
 6         for(i=0;i){
 7             for(j=0;j<=i;j++){
 8                 if(j==0 || j==i){s[i][j]=1;}
 9                 else{s[i][j]=s[i-1][j]+s[i-1][j-1];}
10             }
11         }
12         for(i=0;i){
13             for(j=0;j<=i;j++){
14                 if(j==i){printf("%d\n",s[i][j]);}
15                 else{printf("%d ",s[i][j]);}
16             }
17         }
18         printf("\n");
19     }
20 }

 

2040  亲和数

 1 #include 
 2 
 3 int qhs(int a){
 4     int i,j,sum,s[50];
 5     s[0]=1;j=1;
 6     for(i=2;i<=a/2;i++){
 7         if(a%i==0){s[j]=i;j++;}
 8     }
 9     sum=0;
10     for(i=0;i s[i];}
11     return sum;
12 }
13 
14 int main(){
15     int n,i,a,b,c,s[100];
16     while(scanf("%d",&n)!=EOF){
17         while(n--){
18             scanf("%d %d",&a,&b);
19             if(qhs(a)==b || qhs(b)==a){printf("YES\n");}
20             else{printf("NO\n");}
21         }
22     }
23 }

 

2042  不容易系列之二

 1 #include 
 2 
 3 int main(){
 4     int n,m,i;
 5     while(scanf("%d",&n)!=EOF){
 6         while(n--){
 7             scanf("%d",&m);
 8             i = 3;
 9             while(m--){i = (i-1)*2;}
10             printf("%d\n",i);
11         }
12 
13     }
14 }

 

2054  A == B ?

#include
#include<string.h>
char a[100000],b[100000];
void change(char s[])
{
    int len,i;
    len=strlen(s);
    if(strstr(s,"."))
    {
        for(i=len-1;s[i]=='0';i--)
        {
            s[i]='\0';
            len--;
        }
    }
    if(s[len-1]=='.')
        s[len-1]='\0';
}
int main()
{
    while(~scanf("%s %s",&a,&b))
    {
        change(a);
        change(b);
        if(strcmp(a,b)==0)
            printf("YES\n");
        else
            printf("NO\n");
    }
    return 0;
}

 

2055  An easy problem

 1 #include 
 2 #include <string.h>
 3 
 4 int f(char a){
 5     if(a>='A'&&a<='Z'){return a-64;}
 6     if(a>='a'&&a<='z'){return 96-a;}
 7 }
 8 
 9 int main(){
10     char a;
11     int n,b,sum;
12     while(scanf("%d",&n)!=EOF){
13         getchar();
14         while(n--){
15             
16             scanf("%c %d",&a,&b);
17             getchar();
18             sum = b + f(a);
19             printf("%d\n",sum);
20             
21         }
22     }
23 }

 

转载于:https://www.cnblogs.com/Ragd0ll/p/10433843.html