CCFCSP试题编号：202009-2试题名称：风险人群筛查

 

#include 
using namespace std;

//判断是否在区域
bool isIn(int xl, int yd, int xr, int yu, int x, int y)
{
	if ((x >= xl && x <= xr) && (y >= yd && y <= yu))
	{
		return true;
	}
	return false;
}

struct position
{
	int a, b;
}po[1005];
int main()
{
	int n, k, t, xl, yd, xr, yu;
	cin >> n >> k >> t >> xl >> yd >> xr >> yu;
	int max = 0;
	int d1 = 0, d2 = 0;
	while (n--)
	{
		max = 0;
		int count = 0;
		for (int i = 0; i < t; i++)
		{
			cin >> po[i].a >> po[i].b;
			if (isIn(xl, yd, xr, yu, po[i].a, po[i].b) == true)
			{
				count++;
			}
			else
			{
				count = 0;
			}
			if (count > max)
			{
				max = count;
			}
		}
		if (max >= k)
		{
			d2++;
		}
		else if (max >= 1)
		{
			d1++;
		}
	}
	cout << d1 + d2 << endl;
	cout << d2 << endl;
}