SQL面试题，判断if的实战应用

有如下表，请对这张表显示那些学生的成绩为及格，那些为不及格

1、创建表，插入数据

CREATE TABLE chapter8 (
	id VARCHAR(255) NULL,
	name VARCHAR(255) NULL,
	class VARCHAR(255) NULL,
	score VARCHAR(255) NULL
);

INSERT INTO chapter8 (id, name, class, score) VALUES('E001', '张通', '一班', '98');
INSERT INTO chapter8 (id, name, class, score) VALUES('E002', '李谷', '一班', '68');
INSERT INTO chapter8 (id, name, class, score) VALUES('E003', '孙凤', '一班', '57');
INSERT INTO chapter8 (id, name, class, score) VALUES('E004', '赵恒', '二班', '47');
INSERT INTO chapter8 (id, name, class, score) VALUES('E005', '王娜', '二班', '84');
INSERT INTO chapter8 (id, name, class, score) VALUES('E006', '李伟', '二班', '70');
INSERT INTO chapter8 (id, name, class, score) VALUES('E007', '刘杰', '三班', '50');
INSERT INTO chapter8 (id, name, class, score) VALUES('E008', '薛李', '三班', '92');
INSERT INTO chapter8 (id, name, class, score) VALUES('E009', '裴军', '三班', '35')

2、实现：

select
id,
name,
score  ,
if(score>=60,"及格","不及格")  result
from chapter8