平面内的3个点只可能有6种结构
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向一个平面内扔3个石子,只有这6种可能,
现在向这个三角形内随机的扔3个石子,统计6个结构的占比,从9个点中选3个点有84种可能,分别占比为
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0.285714 |
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11 |
0.130952 |
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34 |
0.404762 |
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8 |
0.095238 |
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0.071429 |
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1 |
0.011905 |
顺序是3>1>2>4>5>6
用网络分类这6个结构
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50827.11 |
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50827.11 |
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50827.11 |
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50827.11 |
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50827.11 |
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50914.58 |
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50914.58 |
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50914.58 |
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50914.58 |
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50914.58 |
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51308.42 |
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51308.42 |
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51308.42 |
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51308.42 |
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69065.23 |
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69478.73 |
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131879.6 |
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131879.6 |
( A, B )---4*11*2---( 1, 0 )( 0, 1 )
当收敛误差为7e-4,B全为0,隐藏层节点数为11个的时候,迭代次数的顺序就是3<1<2<4<5<6
改变三角形的形状
这个三角形有14个点,取3个点有364种可能,
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33 |
0.090659 |
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165 |
0.453297 |
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144 |
0.395604 |
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0.032967 |
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9 |
0.024725 |
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0.002747 |
6个结构的占比为2>3>1>4>5>6
( A, B )---4*105*2---( 1, 0 )( 0, 1 )
其他参数不变,把隐藏层节点数调整为105个点时,
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52162.32 |
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52162.32 |
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52162.32 |
迭代次数的顺序就是2<3<1<4<5<6.因为搜索区域内2的结构更多因此更容易找到,所以迭代次数更小。而结构6的数量占比更少,所以迭代次数更大。
综合比较这两组数据,暗示了一种可能。增加隐藏层节点数就是在拉伸这个三角形,因为搜索形状的变化改变了6个结构的占比,并导致搜索难度的改变,最终决定了迭代次数的顺序。
计算机验算两组数据,都随机扔了1000次。
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303 |
0.3 |
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93 |
0.09 |
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126 |
0.13 |
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475 |
0.48 |
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383 |
0.38 |
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0.37 |
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0.11 |
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40 |
0.04 |
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0.07 |
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0.01 |
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0.01 |
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0 |
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3>1>2>4>5>6 |
2>3>1>4>5>6 |