js数组中对象去重的方法

一个数组中含有对象，并且去除数组中重复的对象

1. id相同的，保留第一个，其它的删除

      let arr = [
        { id: 0, name: "张三" },
        { id: 1, name: "李四" },
        { id: 2, name: "王五" },
        { id: 3, name: "赵六" },
        { id: 1, name: "孙七" },
        { id: 2, name: "周八" },
        { id: 2, name: "吴九" },
        { id: 3, name: "郑十" },
      ];

        const removeDuplicateObj = (arr) => {
          let obj = {};
          arr = arr.reduce((newArr, next) => {
            obj[next.id] ? "" : (obj[next.id] = true && newArr.push(next));
            return newArr;
          }, []);
          return arr;
        };

        console.log(removeDuplicateObj(arr));

2. id相同的，保留第一个，其它的删除------------- for循环方法

      let arr = [
        { id: 0, name: "张三" },
        { id: 1, name: "李四" },
        { id: 2, name: "王五" },
        { id: 3, name: "赵六" },
        { id: 1, name: "孙七" },
        { id: 2, name: "周八" },
        { id: 2, name: "吴九" },
        { id: 3, name: "郑十" },
      ];

      const removeDuplicateObj = (arr) => {
        let newArr = []
        let obj = {};
        for (var i = 0; i < arr.length; i++) {
          if (!obj[arr[i].id]) {
            newArr.push(arr[i]);
            obj[arr[i].id] = true;
          }
        }
        return newArr
      };

      console.log(removeDuplicateObj(arr));

3. 判断对象中的每一个属性，若其对应的属性值都相同，则去重

      let arr = [
        { id: 0, name: "张三", age: 23 },
        { id: 1, name: "李四", age: 23 },
        { id: 2, name: "王五", age: 24 },
        { id: 3, name: "赵六", age: 25 },
        { id: 1, name: "孙七", age: 23 },
        { id: 2, name: "周八", age: 24 },
        { id: 2, name: "吴九", age: 26 },
        { id: 3, name: "郑十", age: 25 },
      ];

      const removeDuplicateObj = (arr) => {
        // 缓存用于记录
        const newArr = [];
        for (const t of arr) {
          // 检查缓存中是否已经存在
          if (
            newArr.find(
              (c) =>
                c.id === t.id &&
                c.age === t.age 
            )
          ) {
            // 已经存在说明以前记录过，现在这个就是多余的，直接忽略
            continue;
          }
          // 不存在就说明以前没遇到过，把它记录下来
          newArr.push(t);
        }

        // 记录结果就是过滤后的结果
        return newArr;
      };

      console.log(removeDuplicateObj(arr));