2018/12/06 L1-022 L1-022 奇偶分家 Java

还是水题, 不过, 之前的我应该是不会写的, 因为要是实现一行输入(使用BufferedReader和InputStreamReader的组合方式), 代码如下:

import java.io.BufferedReader;
import java.io.InputStreamReader;

public class Main {
    private static int oddNum = 0;  // 记录奇数的数量
    private static int evenNum = 0;  // 记录偶数的数量
    
    public static void main(String[] args) throws Exception{
        BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
        int n = Integer.parseInt(br.readLine());
        String[] str = new String[n];
        str = br.readLine().split(" ");
        for (int i=0; i) {
            OddOrEven(Integer.parseInt(str[i]));
        }
        System.out.print(oddNum + " " + evenNum);
    }
    public static void OddOrEven(int num) {
        if(num % 2 ==0) {
            // 意味着这个数是偶数
            evenNum++;
        } else {
            oddNum++;
        }
    }

}

 

转载于:https://www.cnblogs.com/huangZ-H/p/10075526.html