9. Palindrome Number {Easy}

Determine whether an integer is a palindrome. An integer is a palindrome when it reads the same backward as forward.

Example 1:

Input: 121
Output: true
Example 2:

Input: -121
Output: false
Explanation: From left to right, it reads -121. From right to left, it becomes 121-. Therefore it is not a palindrome.
Example 3:

Input: 10
Output: false
Explanation: Reads 01 from right to left. Therefore it is not a palindrome.
Follow up:

Coud you solve it without converting the integer to a string?

my solution:

class Solution:
    def isPalindrome(self, x):
        """
        :type x: int
        :rtype: bool
        """
        if x < 0: return False
        l = []
        while x > 0:
            l.append(x % 10)
            x = x // 10
        l_copy = l.copy()
        l.reverse()
        if l == l_copy:
            return True
        else:
            return False

AustinBaird12's solution:

class Solution:
    def isPalindrome(self, x):
        """
        :type x: int
        :rtype: bool
        """ 
        y = str(x)     # Convert input to a String
        z = y[::-1]    # Save another string as the reversed input
    
        if y == z:
            return True
        else:
            return False
    
        # By nature of palindromes, if the original string it exactly the same
        # as the reversed string, it is by definition a Palindrome.

uchaan's solution:

class Solution(object):
    def isPalindrome(self, x):
        """
        :type x: int
        :rtype: bool
        """
        stx=str(x)
        rvstx=''.join(reversed(stx))

        return (stx==rvstx)

最简洁版 from CodingKido:

return (str(x)==str(x)[::-1])