Post 请求获取form-data格式中body参数及文件

public void getPostFormData(HttpServletRequest req, HttpServletResponse resp) throws Exception {```
        resp.setCharacterEncoding(CharEncoding.UTF_8);
        resp.setContentType("application/json;charset=UTF-8");
        resp.setStatus(HttpServletResponse.SC_OK);
        Map parameterMap = req.getParameterMap();
        CommonsMultipartResolver resolver =new CommonsMultipartResolver(
                req.getSession().getServletContext());
        MultipartFile file=null;
        if(resolver.isMultipart(req)){
            MultipartHttpServletRequest mult=(MultipartHttpServletRequest)req;
            Iterator it=mult.getFileNames();
            while(it.hasNext()){
                file=mult.getFile(it.next().toString());
            }
        }
        File file1 = transferToFile(file);
        Map param = new HashMap();
        if (parameterMap != null && parameterMap.size() > 0) {
            for (Iterator iter = parameterMap.entrySet().iterator(); iter.hasNext(); ) {
                Map.Entry element = (Map.Entry) iter.next();
                //key值
                String strKey = String.valueOf(element.getKey()).trim();
                if(!ValidateUtil.isEmpty(strKey) && strKey.contains("?")){
                    strKey=strKey.replace("?","");
                }
                //value,数组形式
                String[] value = (String[]) element.getValue();
                param.put(strKey,value);
                if(!ValidateUtil.isEmpty(value)){
                    param.put(strKey,value[0]);
                }

            }
        }
   
}

private File transferToFile(MultipartFile multipartFile) {
//        选择用缓冲区来实现这个转换即使用java 创建的临时文件 使用 MultipartFile.transferto()方法 。
        File file = null;
        try {
            String originalFilename = multipartFile.getOriginalFilename();
            String[] filename = originalFilename.split("\\.");
            file=File.createTempFile(filename[0], filename[1]);
            multipartFile.transferTo(file);
            file.deleteOnExit();
        } catch (IOException e) {
            e.printStackTrace();
        }
        return file;
    }