程序报段错误

在代码第51行“(*str) = (*next)”处报错:Program received signal SIGSEGV, Segmentation fault

描述如下:

编写一个函数,删除一个字符串的一部分。函数原型如下:

int del_substr (char *str, char const *substr)

举个例子,假定str指向ABCDEFG. 如果substr指向FGH, CDF或XABC, 函数应该返回0,str未做任何修改。但如果substr指向CDE, 函数就把str修改为指向ABFG.

代码实现如下:

#include#include/*

** If the string "substr" appears in "str", delete it.

*/

//#define NULL 0 /* null pointer */

//#define NUL ’\0’ /* null byte */

#define TRUE 1

#define FALSE 0

/*

** See if the substring beginning at ’str’ matches the string ’want’.  If

** so, return a pointer to the first character in ’str’ after the match.

*/

char *match (char *str, char const *want)

{

while (*want != '\0') {

if (*str++ != *want++) {

return NULL;

}

}

return str;

}

int del_substr (char *str, char const *substr)

{

char *next = NULL;

char *res = str;

/*

** Look through the string for the first occurrence of the substring.

*/

while( *str != '\0' ){

next = match( str, substr );

if( next != NULL )

break;

str++;

}

printf("##next: %s\n", next);

printf("##str: %s\n", str);

/*

** If we reached the end of the string, then the substring was not

** found.

*/

if( *str == '\0' )

return FALSE;

/*

** Delete the substring by copying the bytes after it over the bytes of

** the substring itself.

*/

while(*next != '\0'){

(*str) = (*next);

printf("##str: %s\n", str);

printf("##next: %s\n", next);

str++;

next++;

}

*str = '\0';

printf("after del_substr result: %s\n", res);

return TRUE;

}

int main()

{

char *str = "ABCDEFG";

char const *sub_str1 = "FGH";

char const *sub_str2 = "DE";

int res = -1;

res = del_substr(str, sub_str2);

// printf("the resust is %s\n", str);

printf("the res is %d\n", res);

return res;

}

报错如下:

38        printf("##next: %s\n", next);

(gdb)

##next: FG

39        printf("##str: %s\n", str);

(gdb)

##str: DEFG

44        if( *str == '\0' )

(gdb)

50        while(*next != '\0'){

(gdb)

51            (*str) = (*next);

(gdb)

Program received signal SIGSEGV, Segmentation fault.

0x0804849f in del_substr (str=0x8048667 "DEFG", substr=0x8048670 "DE")

at del_substr.c:51

51            (*str) = (*next);

(gdb)

--------------------------------分割线--------------------------------

知道问题出在哪里了

main函数最开始的变量初始化

char *str = "ABCDEFG";

str指向的是只读常量区,所以执行到(*str) = (*next);会报错,该语句试图改变只读常量区里的值时,操作系统向程序发送了一个信号,告诉程序操作系统检测到了非法的内存访问,为了防止内存空间被破坏,操作系统提前终止了该程序的运行;

用数组声明即可

char str[] = "ABCDEFG";

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