MySQL模糊匹配之like和like concat
SET NAMES utf8mb4;
SET FOREIGN_KEY_CHECKS = 0;
-- ----------------------------
-- Table structure for user
-- ----------------------------
DROP TABLE IF EXISTS `user`;
CREATE TABLE `user` (
`id` int(10) UNSIGNED NOT NULL AUTO_INCREMENT,
`name` varchar(255) CHARACTER SET utf8 COLLATE utf8_general_ci NULL DEFAULT NULL,
`age` int(11) NULL DEFAULT NULL,
`create_time` datetime(0) NOT NULL DEFAULT CURRENT_TIMESTAMP(0) ON UPDATE CURRENT_TIMESTAMP(0),
PRIMARY KEY (`id`) USING BTREE
) ENGINE = InnoDB CHARACTER SET = utf8 COLLATE = utf8_general_ci ROW_FORMAT = Dynamic;
-- ----------------------------
-- Records of user
-- ----------------------------
INSERT INTO `user` VALUES (8, 'test1飞龙', 11, '2021-01-29 09:52:58');
INSERT INTO `user` VALUES (9, 'test2梦魇', 12, '2021-01-29 09:52:41');
INSERT INTO `user` VALUES (10, 'test3龙狼', 13, '2021-01-29 09:52:34');
INSERT INTO `user` VALUES (11, 'test4狼人', 14, '2021-01-29 09:53:09');
INSERT INTO `user` VALUES (12, 'test5龙文', 15, '2021-01-29 09:53:04');
INSERT INTO `user` VALUES (13, 'test1', 11, '2021-01-29 09:53:12');
INSERT INTO `user` VALUES (14, 'test2', 12, '2021-01-29 09:53:12');
INSERT INTO `user` VALUES (15, 'test3', 13, '2021-01-29 09:53:12');
INSERT INTO `user` VALUES (16, 'test4', 14, '2021-01-29 09:53:12');
INSERT INTO `user` VALUES (17, 'test5', 15, '2021-01-29 09:53:12');
SET FOREIGN_KEY_CHECKS = 1;
like '%关键字%'%：表示任意0个或多个字符。可匹配任意类型和长度的字符，有些情况下若是中文，请使用两个百 分号（%%）表示
SELECT
*
FROM
`user`
WHERE
`name` LIKE '%2%'
OR age LIKE '%3%'
-----------------------------------
# 查询name中带2或者age带3的数据
id name age create_time
9 test2梦魇 12 2021-01-29 09:52:41
10 test3龙狼 13 2021-01-29 09:52:34
14 test2 12 2021-01-29 09:53:12
15 test3 13 2021-01-29 09:53:12
# 扩展写法 LiKE CONCAT
如果多个字段或判断，写起来不是很方便, 如果是同一个关键字，可以使用 LiKE CONCAT
SELECT
*
FROM
`user`
WHERE
CONCAT( NAME, age ) LIKE CONCAT( '%', '2', '%' )
#结果：
id name age create_time
9 test2梦魇 12 2021-01-29 09:52:41
14 test2 12 2021-01-29 09:53:12
--------------------------------------------------------------------------
# 请注意，以上写法，如果字段中存在null，则无法正确匹配
# 更新id=14的age=null
UPDATE `user` SET age=NULL WHERE name='test2';
SELECT
*
FROM
`user`
WHERE
CONCAT( NAME, age ) LIKE CONCAT( '%', '2', '%' )
#结果：
id name age create_time
9 test2梦魇 12 2021-01-29 09:52:41
--------------------------------------------------------------------------
# 解决方案1
# 增加 IFNULL
SELECT
*
FROM
`user`
WHERE
CONCAT( IFNULL(name, ''), IFNULL(age, '') ) LIKE CONCAT( '%', '2', '%' )
#结果：
id name age create_time
9 test2梦魇 12 2021-01-29 09:52:41
14 test2 2021-01-29 10:34:36
--------------------------------------------------------------------------
# 解决方案2
SELECT
*
FROM
`user`
WHERE
CONCAT( `name` ) LIKE CONCAT( '%', '2', '%' )
or
CONCAT( age) LIKE CONCAT( '%', '2', '%' )
#结果：
id name age create_time
9 test2梦魇 12 2021-01-29 09:52:41
14 test2 2021-01-29 10:34:36
like '%关键字%关键字%'同时匹配多个关键字
SELECT
*
FROM
`user`
WHERE
`name` LIKE '%2%梦%'
# 结果
id name age create_time
9 test2梦魇 12 2021-01-29 09:52:41
_： 表示任意单个字符。匹配单个任意字符，限制表达式的字符长度
# 1个_
SELECT
*
FROM
`user`
WHERE
`name` LIKE 'test_'
id name age create_time
13 test1 11 2021-01-29 09:53:12
14 test2 2021-01-29 10:34:36
15 test3 13 2021-01-29 09:53:12
16 test4 14 2021-01-29 09:53:12
17 test5 15 2021-01-29 11:20:54
--------------------------------------------
# 3个_
SELECT
*
FROM
`user`
WHERE
`name` LIKE 'test___'
id name age create_time
8 test1飞龙 11 2021-01-29 09:52:58
9 test2梦魇 12 2021-01-29 09:52:41
10 test3龙狼 13 2021-01-29 09:52:34
11 test4狼人 14 2021-01-29 09:53:09
12 test5龙文 15 2021-01-29 09:53:04