cte 查询所有上级

create table tb(id int ,fid int ,name nvarchar ( 10 ))
insert into tb select 1 , 0 , ' 百度知道 '
insert into tb select 2 , 1 , ' 电脑/网络 '
insert into tb select 3 , 2 , ' 程序设计 '
insert into tb select 4 , 3 , ' 数据库程序设计 '
insert into tb select 5 , 1 , ' 电脑/单机 '
go
declare @current nvarchar ( 10 )
set @current = ' 程序设计 '
; with cte as (
select * from tb where name = @current
union all
select a. * from tb a inner join cte b on a.id = b.fid
),c1 as (
select top 100 name from cte order by fid
)
select stuff (( select ' _ ' + [ name ] from c1 for xml path( '' )), 1 , 1 , '' )
go
drop table tb

 

简单ID查询方式

declare @current int
set @current=3

;with cte as(
select * from tb where id=@current
union all
select a.* from tb a inner join cte b on a.id=b.fid
)
select id, name from cte order by fid