poj1171

pairs的组合只可能是3+3或者3+4

所以其余长度的单词无需记录

把记录后的单词n^2枚举pair

View Code

#include <iostream>
#include <cstdlib>
#include <cstring>
#include <cstdio>
using namespace std;

char pre1[30] = "qwertyuiopasdfghjklzxcvbnm";
int pre2[30] =
{ 7, 6, 1, 2, 2, 5, 4, 1, 3, 5, 2, 1, 4, 6, 5, 5, 7, 6, 3, 7, 7, 4, 6, 5, 2, 5 };
int value[300];
char collected[10];
char word[40005][10];
int n, ans;

int cal(char * st, int len)
{
    int ret = 0;
    for (int i = 0; i < len; i++)
        ret += value[st[i]];
    return ret;
}

bool ok(char *a, char *b)
{
    int len1 = strlen(a);
    int len2 = strlen(b);
    int len = strlen(collected);
    if (len1 + len2 > len)
        return false;
    bool vis[10];
    memset(vis, 0, sizeof(vis));
    for (int i = 0; i < len1; i++)
    {
        bool did = false;
        for (int j = 0; j < len; j++)
            if (collected[j] == a[i] && !vis[j])
            {
                vis[j] = true;
                did = true;
                break;
            }
        if (!did)
            return false;
    }
    for (int i = 0; i < len2; i++)
    {
        bool did = false;
        for (int j = 0; j < len; j++)
            if (collected[j] == b[i] && !vis[j])
            {
                vis[j] = true;
                did = true;
                break;
            }
        if (!did)
            return false;
    }
    return true;
}

int main()
{
    //freopen("t.txt", "r", stdin);
    for (int i = 0; i < 26; i++)
        value[pre1[i]] = pre2[i];
    scanf("%s", collected);
    int lenc = strlen(collected);
    char now[10];
    n = 0;
    ans = 0;
    while (scanf("%s", now), strcmp(".", now))
    {
        int len = strlen(now);
        if (len > lenc || !ok(now, ""))
            continue;
        ans = max(ans, cal(now, len));
        if (len <= lenc / 2 + (lenc & 1))
            strcpy(word[n++], now);
    }
    for (int i = 0; i < n - 1; i++)
        for (int j = i; j < n; j++)
            if (ok(word[i], word[j]))
                ans = max(ans, cal(word[i], strlen(word[i])) + cal(word[j], strlen(word[j])));
    printf("%d\n", ans);
    return 0;
}