HDU 1985 Conversions

http://acm.hdu.edu.cn/showproblem.php?pid=1985

小学计算题

View Code

#include <iostream>

#include <string>

using namespace std;

int main()

{

    int t;

    scanf("%d",&t);

    for(int cas=1;cas<=t;cas++)

    {

        double n;

        string d;

        cin >> n >> d;

        if(d=="kg")

            printf("%d %.4lf lb\n",cas,n*2.2046);

        else if(d=="lb")

            printf("%d %.4lf kg\n",cas,n*0.4536);

        else if(d=="g")

            printf("%d %.4lf l\n",cas,n*3.7854);

        else if(d=="l")

            printf("%d %.4lf g\n",cas,n*0.2642);

    }

    return 0;

}