Section 1.1 ride

这道题是比较两个字符串根据A = 1，Z = 26这种关系来进行乘法运算得到的值a和b

Mod 47之后值的关系，相等输出“GO”,不相等输出“STAY”。

 

/*
ID:yucept21
LANG:C++
TASK:ride
*/

#include<cstdio>
#include<cstring>
#include<cstdlib>

int main()
{
    freopen( "ride.in", "r", stdin);
    freopen( "ride.out", "w", stdout);
    char s1[6], s2[6];
    long a = 1, b = 1;
    scanf( "%s%s", s1, s2);
    int len1 = strlen( s1);
    int len2 = strlen( s2);
    for( int i = 0; i < len1; i ++)
        a *= ( s1[i] - 'A' + 1);
    for( int i = 0; i < len2; i ++)
        b *= ( s2[i] - 'A' + 1);
    a %= 47;
    b %= 47;
    if( a == b)
        printf( "GO\n");
    else
        printf( "STAY\n");
    return 0;
}