C#比较两时间大小

 

代码

// 1、比较时间大小的实验
   string  st1 = " 12:13 " ;
    string  st2 = " 14:14 " ;
   DateTime dt1 = Convert.ToDateTime(st1);
   DateTime dt2 = Convert.ToDateTime(st2);
   DateTime dt3 = DateTime.Now;
    if (DateTime.Compare(dt1,dt2) > 0 )
    msg.Text = st1 + " > " + st2;
    else
    msg.Text = st1 + " < " + st2;
   msg.Text += " \r\n " + dt1.ToString();
    if (DateTime.Compare(dt1,dt3) > 0 )
    msg.Text += " \r\n " + st1 + " > " + dt3.ToString();
    else
    msg.Text += " \r\n " + st1 + " < " + dt3.ToString();

// 2、计算两个时间差值的函数，返回时间差的绝对值：
         private   string  DateDiff(DateTime DateTime1,DateTime DateTime2)
        {
             string  dateDiff = null ;
             try
            {
                TimeSpan ts1 = new   TimeSpan(DateTime1.Ticks);
                TimeSpan ts2 = new   TimeSpan(DateTime2.Ticks);
                TimeSpan ts = ts1.Subtract(ts2).Duration();
                dateDiff = ts.Days.ToString() + " 天 "
                         + ts.Hours.ToString() + " 小时 "
                         + ts.Minutes.ToString() + " 分钟 "
                         + ts.Seconds.ToString() + " 秒 " ;
            }
             catch
            {

            }
             return  dateDiff;
        }

// 3、实现计算DateTime1－36天＝DateTime2的功能

   TimeSpan ts = new  TimeSpan( 40 , 0 , 0 , 0 );
   DateTime dt2 = DateTime.Now.Subtract(ts);
   msg.Text = DateTime.Now.ToString() + " - " + ts.Days.ToString() + " 天\r\n " ;
   msg.Text += dt2.ToString();