淘宝ued - 前端智勇大闯关(第三季)答案(更新)
淘宝ued - 前端智勇大闯关(第三季)答案(更新)
下午在微博上看到了淘宝智勇大闯关第三季的信息，感觉挺有意思的，于是就尝试做了下。附上题目地址：
也可到独立博客查看：前端智勇大闯关(第三季)答案
第1题 突破，带锁的门
方法1
这题相对比较简单，查看源码即可看到提示信息：
1 <!-- 2 -==================================== 3 - 调用powder.blow()显示指纹痕迹！ 4 -==================================== 5 -->
只要在控制台里多次调用powder.blow()函数即可看到图片上的指纹信息。然后尝试组合这几个数便可过关。如下图所示：
方法2
另一种比较简单的方法就是加断点监控pwd的值，如下图所示，答案就是数组里的三个数字：
第2题 激光，前进的方向
这题主要考察css3的transform属性，首先在右下角的灰色小块(#ma)上添加样式，然后调整top值，最终样式如下：
1 #ma { 2 top: 549px; 3 left: 960px; 4 -webkit-transform: rotate(-82deg); 5 }
然后会看到界面中又多了一个黑点，再调整左上方的灰色小块(#mb)，调整方法同上，最终样式为：
1 #mb { 2 left: 550px; 3 top: 425px; 4 -webkit-transform: rotate(169deg); 5 }
最终结果如下图，即可过关。
第3题 坐标，隐藏的线索
这题主要考察canvas绘图，查看源码时，页面中会有提示信息(一大串数字)，这些数字其实就是绘制坐标。
var str = "0,0,12,12 12,0,12,12 24,0,12,12 36,0,12,12 48,0,12,12 60,0,12,12 72,0,12,12 120,0,12,12 132,0,12,12 144,0,12,12 168,0,12,12 180,0,12,12 192,0,12,12 204,0,12,12 216,0,12,12 228,0,12,12 240,0,12,12 0,12,12,12 72,12,12,12 96,12,12,12 108,12,12,12 120,12,12,12 144,12,12,12 168,12,12,12 240,12,12,12 0,24,12,12 24,24,12,12 36,24,12,12 48,24,12,12 72,24,12,12 120,24,12,12 132,24,12,12 144,24,12,12 168,24,12,12 192,24,12,12 204,24,12,12 216,24,12,12 240,24,12,12 0,36,12,12 24,36,12,12 36,36,12,12 48,36,12,12 72,36,12,12 96,36,12,12 108,36,12,12 144,36,12,12 168,36,12,12 192,36,12,12 204,36,12,12 216,36,12,12 240,36,12,12 0,48,12,12 24,48,12,12 36,48,12,12 48,48,12,12 72,48,12,12 108,48,12,12 144,48,12,12 168,48,12,12 192,48,12,12 204,48,12,12 216,48,12,12 240,48,12,12 0,60,12,12 72,60,12,12 96,60,12,12 132,60,12,12 168,60,12,12 240,60,12,12 0,72,12,12 12,72,12,12 24,72,12,12 36,72,12,12 48,72,12,12 60,72,12,12 72,72,12,12 96,72,12,12 120,72,12,12 144,72,12,12 168,72,12,12 180,72,12,12 192,72,12,12 204,72,12,12 216,72,12,12 228,72,12,12 240,72,12,12 108,84,12,12 0,96,12,12 12,96,12,12 24,96,12,12 36,96,12,12 48,96,12,12 72,96,12,12 84,96,12,12 96,96,12,12 132,96,12,12 156,96,12,12 180,96,12,12 204,96,12,12 228,96,12,12 0,108,12,12 24,108,12,12 36,108,12,12 60,108,12,12 120,108,12,12 132,108,12,12 144,108,12,12 156,108,12,12 168,108,12,12 216,108,12,12 240,108,12,12 12,120,12,12 36,120,12,12 48,120,12,12 60,120,12,12 72,120,12,12 84,120,12,12 108,120,12,12 120,120,12,12 144,120,12,12 168,120,12,12 180,120,12,12 228,120,12,12 24,132,12,12 36,132,12,12 60,132,12,12 84,132,12,12 96,132,12,12 108,132,12,12 120,132,12,12 132,132,12,12 144,132,12,12 156,132,12,12 168,132,12,12 204,132,12,12 216,132,12,12 0,144,12,12 12,144,12,12 24,144,12,12 48,144,12,12 72,144,12,12 84,144,12,12 96,144,12,12 108,144,12,12 144,144,12,12 180,144,12,12 204,144,12,12 228,144,12,12 96,156,12,12 108,156,12,12 120,156,12,12 144,156,12,12 180,156,12,12 204,156,12,12 216,156,12,12 228,156,12,12 240,156,12,12 0,168,12,12 12,168,12,12 24,168,12,12 36,168,12,12 48,168,12,12 60,168,12,12 72,168,12,12 96,168,12,12 108,168,12,12 120,168,12,12 132,168,12,12 156,168,12,12 192,168,12,12 204,168,12,12 216,168,12,12 228,168,12,12 0,180,12,12 72,180,12,12 108,180,12,12 180,180,12,12 192,180,12,12 204,180,12,12 216,180,12,12 228,180,12,12 0,192,12,12 24,192,12,12 36,192,12,12 48,192,12,12 72,192,12,12 96,192,12,12 108,192,12,12 120,192,12,12 132,192,12,12 156,192,12,12 192,192,12,12 228,192,12,12 0,204,12,12 24,204,12,12 36,204,12,12 48,204,12,12 72,204,12,12 96,204,12,12 120,204,12,12 132,204,12,12 144,204,12,12 156,204,12,12 168,204,12,12 180,204,12,12 204,204,12,12 216,204,12,12 0,216,12,12 24,216,12,12 36,216,12,12 48,216,12,12 72,216,12,12 96,216,12,12 144,216,12,12 168,216,12,12 180,216,12,12 204,216,12,12 216,216,12,12 0,228,12,12 72,228,12,12 96,228,12,12 132,228,12,12 144,228,12,12 156,228,12,12 168,228,12,12 180,228,12,12 204,228,12,12 216,228,12,12 0,240,12,12 12,240,12,12 24,240,12,12 36,240,12,12 48,240,12,12 60,240,12,12 72,240,12,12 96,240,12,12 108,240,12,12 120,240,12,12 144,240,12,12 228,240,12,12" var arr = str.split(" "); var drawing = document.getElementById('qr-canvas'); var context = drawing.getContext('2d'); context.fillStyle = "#000"; for(var i = 0; i < arr.length; i++){ var tmp = arr[i].split(','); context.fillRect(tmp[0],tmp[1],tmp[2],tmp[3]); }
把页面中的数字信息放入上面代码中的字符串str中，然后将代码复制到控制台执行即可过关。
第4题 图案，疯狂的猜测
第四题考察的知识面比较广，每个人的题目可能也不一样。答案涉及到：
1 操作系统: ubuntu 2 管理器: npm 3 开源程序名: wordpress 4 IDE: sublime 5 ps快捷键: v 6 网址：stackoverflow.com 还有一个是 w3.org 7 淘宝图标方案：sprite 8 圆形图案(标记语言): php 9 模版语言: Jade 10 样式语言: less 11 前端库(.zip...): underscore
第5题 寻找，无尽的房间
方法一
最简答的方法就是用NEXT ROOM中的数字替换地址栏中&room= 中的数字，然后把每次的#message信息积累下来。这算是一个本办法吧，但可以过关。
方法二
但是控制台中有提示信息：
jQuery is ready for you.
于是可以用jQuery通过ajax来请求，最后获得下一关的地址，代码如下
(function(){
var str = '';
var startRoom = $("#next-room").text();
getMessage(startRoom);
function getMessage(room){
$.ajax({
url: location.pathname + location.search.replace(/room\=\d+/, 'room=' + room),
dataType: 'html',
type: 'get',
success: function(res) {
var nextRoom = $("#next-room", $(res)).text();
if (nextRoom) {
str += $("#message", $(res)).text();
console.log("正在进入" + nextRoom + "号房间，请稍候...");
setTimeout(function() {
getMessage(nextRoom);
}, 3000);
}else{
str += $("#message", $(res)).text();
console.log('完整的message信息是：' + str);
console.log('下一关的地址是' + location.host + str.substring(str.indexOf('/')));
}
}
});
}
})()截图如下：
第6题 消除! 最后的任务
控制台输入：
var t=KISSY; e=t.DOM; window.location=Base64.decode(e.attr("#page","data-p"));
上面只是自己做的结果，大家有好的答案的话欢迎补充。
分类:
html&css,
javascript