引用
1. (10%) LC-3汇编程序设计:
R0中存有整数
s,输入一位整数
m,看
s能否被
m整除,是则输出1,反之则输出0。
Letter | ASCII
'0' | x0030
2. (10%) C程序设计:
写方法check(char* s),再使用main()来让用户输入字符串,调用check,输出结果。
check:比较s中的“)”与“(”的个数,如果同时满足以下两个条件,返回1,反之0:
1)个数相同;
2)从首字符开始,遇到的“)”的个数从来没有超过“(”的。
解答:
1. test1.asm
; Written by RednaxelaFX, 2008/01/09
; Copy original R0 to R1 to keep the value from being overwritten by TRAP IN
; Use R3 for stripping off ASCII '0'
; Use R4 to keep track of the final output
;
.ORIG x3000
ADD R1, R0, #0 ; R1 = R0 = s
LD R3, A2I
AND R4, R4, #0
ADD R4, R4, #1
INPUT TRAP x23
ADD R0, R0, R3 ; R0 = m
NOT R0
ADD R0, R0, #1 ; R0 = -R0
MOD ADD R1, R1, R0 ; s = s - m
BRz OUTPUT1
BRp MOD
OUTPUT0 ADD R4, R4, #-1
OUTPUT1 ADD R0, R4, #0
TRAP x21
HALT
A2I .FILL x-30
.END
2. test2.c
/*
* Written by RednaxelaFX, 2008/01/09
*/
#include <stdio.h>
int check( char* s ) {
char* ptr;
int diff = 0;
ptr = s;
for ( ; ( '\0' != *ptr ) && ( diff >= 0 ); ++ptr ) {
if ( '(' == *ptr) {
++diff;
} else if ( ')' == *ptr ) {
--diff;
}
}
return diff ? 0 : 1;
}
void main( ) {
char input[50]; // input buffer
int result;
printf( "Enter a string: " );
scanf( "%s", input );
result = check( input );
printf("result is: %d\n", result);
}