/* rain.c -- 针对若干年的降水量数据,计算年降水总量,年降水平均量,以及月降水平均量 */ #include <stdio.h> #define MONTHS 12 // 一年的月份 #define YEARS 5 // 降水量数据的年数 int main (void) { // 把数组初始化为2000至2004年的降水量数据 const float rain[YEARS][MONTHS] = { {4.3,4.3,4.3,3.0,2.0,1.2,0.2,0.2,0.4,2.4,3.5,6.6}, {8.5,8.2,1.2,1.6,2.4,0.0,5.2,0.9,0.3,0.9,1.4,7.3}, {9.1,8.5,6.7,4.3,2.1,0.8,0.2,0.2,1.1,2.3,6.1,8.4}, {7.2,9.9,8.4,3.3,1.2,0.8,0.4,0.0,0.6,1.7,4.3,6.2}, {7.6,5.6,3.8,2.8,3.8,0.2,0.0,0.0,0.0,1.3,2.6,5.2} }; int year, month; float subtot; // 对于每一年,各月的总降水量 float total; // 所有年度的总降水量 printf ("YEAR RAINFALL (inches)\n"); for (year =0; total = 0; year < YEARS; year++) { // 对于每一年,各月的总降水量 for (month = 0, subtot = 0; month < MONTHS; month++) subtot += rain[year][month]; printf ("%5d %15.1f\n", 2000 + year, subtot); total += subtot; // 所有年度的总降水量 } printf ("\n The yearly average is %.1f inches.\n\n", total/YEARS); printf (" MONTHLY AVERAGES: \n\n"); printf (" Jan Feb Mar Apr May Jun Jul Aug Sep Oct "); printf (" Nov Dec\n"); for (month = 0; month < MONTHS; month++) { // 对于每个月,各年该月份的总降水量 for (year =0, subtot = 0; year < YEARS; year++) subtot += rain[year][month]; printf ("%4.1f ", subtot/YEARS); } printf ("\n"); return 0; }
因为在for (year =0; total = 0; year < YEARS; year++)里多了个;,所以才报错。
搞了好久才发现,真是不仔细。