jqGrid学习 -------------- 配置json

IE8,FF3以及Chrome 3已经支持JSON,配置:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>My First Grid</title>
 
<link rel="stylesheet" type="text/css" media="screen" href="css/ui-lightness/jquery-ui-1.7.1.custom.css" />
<link rel="stylesheet" type="text/css" media="screen" href="css/ui.jqgrid.css" />
 
<script src="js/jquery-1.3.2.min.js" type="text/javascript"></script>
<script src="js/i18n/grid.locale-en.js" type="text/javascript"></script>
<script type="text/javascript">
	jQuery.jgrid.useJSON = true;
</script>
<script src="js/jquery.jqGrid.min.js" type="text/javascript"></script>
 
</head>
<body>
...
</body>
</html>


要注意下面这段代码
<script type="text/javascript">
	jQuery.jgrid.useJSON = true;
</script>

这段代码要放到语言包之后jqGrid.js文件之前。
如果浏览器不支持JSON,那么我们只能用eval函数解析json。

除了jqGrid本身提供对json的类库外,我们可以使用JSON.parse来处理JSON,配置如下:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>My First Grid</title>
 
<link rel="stylesheet" type="text/css" media="screen" href="css/ui-lightness/jquery-ui-1.7.1.custom.css" />
<link rel="stylesheet" type="text/css" media="screen" href="css/ui.jqgrid.css" />
 
<script src="js/json2.js" type="text/javascript"></script>
<script src="js/jquery-1.3.2.min.js" type="text/javascript"></script>
<script src="js/i18n/grid.locale-en.js" type="text/javascript"></script>
<script src="js/jquery.jqGrid.min.js" type="text/javascript"></script>
<script type="text/javascript">
   jQuery.extend(jQuery.jgrid,{
      parse:function(jsstring) {
         return JSON.parse(jsstring);
      }
   });
</script>
 
</head>
<body>
...
</body>
</html>

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