Project Euler 6 Sum square difference

Project Euler 6 Sum square difference

'''
The sum of the squares of the first ten natural numbers is,
12 + 22 + ... + 102 = 385
The square of the sum of the first ten natural numbers is,
(1 + 2 + ... + 10)2 = 552 = 3025
Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025  385 = 2640.
Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.
'''
from math import *

def getm(i):
    return i*i

            
i=1 
s=0
while i<=100:
   s+=getm(i)
   i+=1 

print s-getm((1+100)*50)