HDU1035 Robot Motion

                                                        Robot Motion

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 5000    Accepted Submission(s): 2311

Problem Description

A robot has been programmed to follow the instructions in its path. Instructions for the next direction the robot is to move are laid down in a grid. The possible instructions are

N north (up the page)
S south (down the page)
E east (to the right on the page)
W west (to the left on the page)

For example, suppose the robot starts on the north (top) side of Grid 1 and starts south (down). The path the robot follows is shown. The robot goes through 10 instructions in the grid before leaving the grid.

Compare what happens in Grid 2: the robot goes through 3 instructions only once, and then starts a loop through 8 instructions, and never exits.

You are to write a program that determines how long it takes a robot to get out of the grid or how the robot loops around.

 

Input

There will be one or more grids for robots to navigate. The data for each is in the following form. On the first line are three integers separated by blanks: the number of rows in the grid, the number of columns in the grid, and the number of the column in which the robot enters from the north. The possible entry columns are numbered starting with one at the left. Then come the rows of the direction instructions. Each grid will have at least one and at most 10 rows and columns of instructions. The lines of instructions contain only the characters N, S, E, or W with no blanks. The end of input is indicated by a row containing 0 0 0.

 

Output

For each grid in the input there is one line of output. Either the robot follows a certain number of instructions and exits the grid on any one the four sides or else the robot follows the instructions on a certain number of locations once, and then the instructions on some number of locations repeatedly. The sample input below corresponds to the two grids above and illustrates the two forms of output. The word "step" is always immediately followed by "(s)" whether or not the number before it is 1.

 

Sample Input

   
   
   
   

    
    
    
    3 6 5 NEESWE WWWESS SNWWWW 4 5 1 SESWE EESNW NWEEN EWSEN 0 0 
   
   
   
   

 

Sample Output

   
   
   
   

    
    
    
    10 step(s) to exit 3 step(s) before a loop of 8 step(s)
   
   
   
   

 

Source

Mid-Central USA 1999


解题思路：其实，也算不上真正意义上的DFS题目，虽说函数名写得时BFS。直接按照题意写，一步一步走，碰到走过的或走出地图就直接结束，处理输出即可。

#include<cstdio> #include<cstring> int n,m,k; char map[12][12]; int flag[12][12]; int step1,loop; int sx,sy; void dfs(int x,int y) {     switch(map[x][y])      //根据地图找方向     {         case 'N':x--;break;         case 'S':x++;break;         case 'W':y--;break;         case 'E':y++;     }     if(flag[x][y])     //当前节点已经走过了，有环     {         loop=step1-flag[x][y];         step1=flag[x][y];         return ;     }     else if(x<0||x>=n||y<0||y>=m)       //走出去了         return ;     flag[x][y]=step1++;     dfs(x,y); } int main() {     while(scanf("%d%d",&n,&m)&&n||m)     {         step1=1;         loop=0;         memset(flag,0,sizeof(flag));         scanf("%d",&k);         sx=0;         sy=k-1;         for(int i=0;i<n;i++)             scanf("%s",map[i]);         flag[sx][sy]=step1++;         dfs(sx,sy);         if(!loop)   //没有环             printf("%d step(s) to exit\n",step1-1);         else        // 有环             printf("%d step(s) before a loop of %d step(s)\n",step1-1,loop);     }     return 0; }