实验七是这本书上第一个比较综合的程序,要求把年份,员工数,收入,和平均工资对应填写在table表中。
开始的时候费了些脑子,但是后来发现自己把问题想复杂了,后来重新梳理了思路,写完代码,debug解决错误。贴这儿算是作个纪念吧
- assume cs:code
- data segment
- db '1975','1976','1977','1978','1979','1980','1981','1982','1983'
- db '1984','1985','1986','1987','1988','1989','1990','1991','1992'
- db '1993','1994','1995' ;年份
- dd 16,22,382,1356,2390,8000,16000,24486,50065,97479,140417,197514
- dd 345980,590827,803530,1183000,1843000,2759000,3753000,4649000,5937000 ;收入
- dw 3,7,9,13,28,38,130,220,476,778,1001,1442,2258,2793,4037,5635,8226
- dw 11542,14430,15257,17800 ;员工数
- data ends
- table segment
- db 21 dup ('year summ ne ?? ')
- table ends
- code segment
- start:
- mov ax,data
- mov ds,ax
- mov bx,168
- mov si,0
- mov di,0
- mov ax,table
- mov es,ax ;初始化
- mov cx,21
- s:
- mov ax,[si]
- mov es:[di],ax
- mov ax,[si+2]
- mov es:[di+2],ax ;年份
- mov bp,[bx]
- mov es:[di+0ah],bp ;员工数
- mov ax,[84+si]
- mov es:[di+5],ax
- mov dx,[86+si]
- mov es:[di+7],dx ;收入
- div bp
- mov es:[di+0dh],ax ;平均收入
- add si,4
- add bx,2
- add di,10h
- loop s
- mov ax,4c00h
- int 21h
- code ends
- end start