今天初学Python写了一个用于计算指定年指定月日历的脚本
我的Python版本:Python 3.4.2
输入:脚本名 年(4位数字,1900-2100) 月(1-2位数字,1-12)
输出:打印的指定年月日历信息
Calendar.py
import os import sys # check if the number of input is legal if len(sys.argv) != 3: print('Invalid input! Example: 2014 12') os.system('pause') # "press any key to continue..." os._exit(0) # terminate this script # check if input(year) is legal print("Year: %s" % sys.argv[1]) if not str(sys.argv[1]).isdigit(): print('Invalid input! Year must be a positive integer') os.system('pause') os._exit(0) elif int(sys.argv[1]) < 1900 or int(sys.argv[1]) > 2100: print('Invalid input! Year must bigger than 1900 and smaller than 2100') os.system('pause') os._exit(0) # check if input(month) is legal print("Month: %s" % sys.argv[2]) if not str(sys.argv[2]).isdigit(): print('Invalid input! Month must be a positive integer') os.system('pause') os._exit(0) elif int(sys.argv[2]) < 1 or int(sys.argv[2]) > 12: print('Invalid input! Year must bigger than 1 and smaller than 12') os.system('pause') os._exit(0) # check: is a leap year or not # param @year: the year input # return: leap: True; not leap: False def IsLeapYear(year): if year % 4 != 0: return False if year % 100 == 0 and year % 400 != 0: return False return True cur_year = sys.argv[1] # the year input cur_month = sys.argv[2] # the month input # counter: the first day in cur_year, cur_month, it indicates the day of week counter = 0 for i in range(1900, int(cur_year)): if IsLeapYear(i): counter += 366 else: counter += 365 days_in_month = [31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31] days_in_month_leap = [31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31] for i in range(1, int(cur_month)): if not IsLeapYear(int(cur_year)): counter += days_in_month[i - 1] else: counter += days_in_month_leap[i - 1] # first_day_in_cur_month: what day is the first day in cur_month first_day_in_cur_month = counter % 7 # name of each month month_name = ['January', 'February', 'March', 'April', 'May', 'June', 'July', 'August', 'September', 'October', 'November', 'December'] # char numbers of each line calendar_width = 45 # print title print() print('=' * calendar_width) space_num = (calendar_width - len(month_name[int(cur_month) - 1])) // 2 sys.stdout.write(" "* space_num) sys.stdout.write(month_name[int(cur_month) - 1]) sys.stdout.write("\n") print('=' * calendar_width) print(" MON TUE WED THU FRI SAT SUN") print('=' * calendar_width) # establish a calendar # calendar = [[0] * 7] * 6 # can not do like this! change a number then change a column calendar = [[0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0, 0]] days_count = 0 if not IsLeapYear(int(cur_year)): days_count = days_in_month[int(cur_month) - 1] else: days_count = days_in_month_leap[int(cur_month) - 1] for i in range(0, days_count): x = (first_day_in_cur_month + i) // 7 y = (first_day_in_cur_month + i) % 7 calendar[x][y] = i + 1 # print calendar for i in range(0, 6): if(i != 0 and calendar[i][0] == 0): # no more days to output then break break; sys.stdout.write(" " * 3) for j in range(0, 7): str_date = str(calendar[i][j]) sys.stdout.write(" ") if str_date == "0": sys.stdout.write(" ") elif len(str_date) == 1: sys.stdout.write(str_date) sys.stdout.write(" ") else: sys.stdout.write(str_date) sys.stdout.write(" " * 3) sys.stdout.write("\n") # print the end line print('=' * calendar_width) print() # os.system('pause')
补充说明:使用 Visual Studio 上的 Python 插件时,调试时要设置命令行输入参数,需要进行如下两步
1)项目→Calendar属性(Calendar为项目名)
2)在属性界面的Debug选项卡中,设置“Script Arguments”,这个程序的输入为“2014 10”
优化:(2014年12月31日)
这3个优化的地方都需要引用calendar,设变量year存储年,变量month存储月
1)遍历一个月的所有天,在本文的代码中,用range(0, days_count),
可以用calendar.monthrange(year, month)代替
2)找出一个月的第一天是星期几,之前用first_day_in_cur_month保存,
可以用calendar.weekday(year, month, 1)代替
calendar.weekday函数中,星期一则返回0,星期二则返回1,以此类推,星期日返回6
3)日历矩阵可以直接用calendar.monthcalendar(year, month)得出
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