spring validator 分析

spring validator 分析

以 BaseCommandController 为例
protected void initApplicationContext() {
  if (this.validators != null) {
   for (int i = 0; i < this.validators.length; i++) {
    if (this.commandClass != null && !this.validators[i].supports(this.commandClass))
     throw new IllegalArgumentException("Validator [" + this.validators[i] +
       "] does not support command class [" +
       this.commandClass.getName() + "]");
   }
  }
 }

子类配置如下

 <bean id="addNewsController" class="AddNewsController" scope="request">
        <property name="formView" value="/management/news/addNews"/>
        <property name="validator" ref="beanValidator"/>
        <property name="successView" value="forward:/management/news/newsList.html"/>
        <property name="commandClass" value="News"/>
        <property name="commandName" value="news"/>
    </bean>

public final void setValidator(Validator validator) {
  this.validators = new Validator[] {validator};
 }

设置Validator数组

在初始化的时候，检验 是否支持command 类型
this.validators[i].supports(this.commandClass)

此support 为 org.springframework.validation.Validator 的所有 实现类的 方法，检验支持检验类的动作。


举例 配置
 <bean id="beanValidator" class="org.springmodules.validation.commons.DefaultBeanValidator">
        <property name="validatorFactory" ref="validatorFactory"/>
    </bean>

DefaultBeanValidator extends AbstractBeanValidator implements Validator

再看实现方法

   /**
     * Checks if the validatorFactory is configured to handle this class.  Will
     * convert the class into a form name, suitable for commons validator.
     *
     * @return <code>true</code> if the validatorFactory supports the class,
     *         or <code>false</code> if not
     * @see #getFormName(Class)
     */
    public boolean supports(Class clazz) {
        boolean canSupport = validatorFactory.hasRulesForBean(getFormName(clazz), getLocale());
        if (log.isDebugEnabled()) {
            log.debug("validatorFactory " + (canSupport ? "does" : "does not")
                + " support class " + clazz + " with form name " + getFormName(clazz));
        }
        return canSupport;
    }

检验是否支持输入类

另一个方法
 /**
     * If <code>useFullyQualifiedClassName</code> is false (default value), this function returns a
     * string containing the uncapitalized, short name for the given class
     * (e.g. myBean for the class com.domain.test.MyBean). Otherwise, it  returns the value
     * returned by <code>Class.getName()</code>.
     *
     * @param cls <code>Class</code> of the bean to be validated.
     * @return the bean name.
     */
    protected String getFormName(Class cls) {
        return (this.useFullyQualifiedClassName) ? cls.getName() : Introspector.decapitalize(ClassUtils.getShortName(cls));
    }
 Introspector.decapitalize(ClassUtils.getShortName(cls) 获得按照西班牙命名法的form 名

这个方法本意是获得以类名为formName 的所有校验配置。

实际上有一个重大的设计缺陷