算法导论7-4思考题-快速排序中的堆栈深度-尾递归技术

The QUICKSORT algorithm of Section 7.1 contains two recursive calls to itself. After the call to PARTITION, the left subarray is recursively sorted and then the right subarray is recursively sorted. The second recursive call in QUICKSORT is not really necessary; it can be avoided by using an iterative control structure. This technique, called tail recursion, is provided automatically by good compilers. Consider the following version of quicksort, which simulates tail recursion. QUICKSORT'(A, p, r) 1 while p < r 2 do ▸ Partition and sort left subarray. 3 q ← PARTITION(A, p, r) 4 QUICKSORT'(A, p, q - 1) 5 p ← q + 1 Argue that QUICKSORT'(A, 1, length[A]) correctly sorts the array A. Compilers usually execute recursive procedures by using a stack that contains pertinent information, including the parameter values, for each recursive call. The information for the most recent call is at the top of the stack, and the information for the initial call is at the bottom. When a procedure is invoked, its information is pushed onto the stack; when it terminates, its information is popped. Since we assume that array parameters are represented by pointers, the information for each procedure call on the stack requires O(1) stack space. The stack depth is the maximum amount of stack space used at any time during a computation. Describe a scenario in which the stack depth of QUICKSORT' is Θ(n) on an n-element input array. Modify the code for QUICKSORT' so that the worst-case stack depth is Θ(lg n). Maintain the O(n lg n) expected running time of the algorithm. 优化的尾递归： QUICKSORT (A, p, r )     while p < r         do Partition and sort the small subarray Þrst         q ← PARTITION(A, p, r )         if q − p < r − q             then QUICKSORT (A, p, q − 1)                     p ← q + 1         else QUICKSORT (A, q + 1, r )                     r ← q − 1