BNUOJ27888：Baby Me

When I was born, I was 5斤2两。Sorry for non-Chinese people. Here's what it means:

1斤=0.5kg

1两=0.05kg

So 5斤2两 means 0.5*5+0.05*2=2.6kg.

Given similar information for other babies, your task is to find out their weights in kg.

Input

The first line contains the number of test cases T(T<=100). Each test case contains a string in format "a斤b两"(1<=a<=10, 1<=b<=9) or "a斤"(1<=a<=10).

The input file will be encoded with UTF-8 without BOM (if you don't know what it is, you can safely ignore it).

Output

For each test case, print the ACCURATE weight in kg (without trailing zeros).

Sample Input

3
5斤2两
7斤3两
6斤

Output for the Sample Input

Case 1: 2.6
Case 2: 3.65
Case 3: 3

Rujia Liu's Present 6: Happy 30th Birthday to Myself
Special thanks: Md. Mahbubul Hasan, Feng Chen

题意：将斤两转化为千克，注意小数后面无意义的0不能留

思路：将整数部分与小数部分分开计算

 

#include <stdio.h>
#include <string.h>
#include <algorithm>
using namespace std;

char str[100];

int main()
{
    int n,len,i,j,head,end,cas = 1;
    double jin,liang,t;
    scanf("%d",&n);
    while(n--)
    {
        jin = liang = 0;
        head = end = 0;
        scanf("%s",str);
        len = strlen(str);
        for(i = 0; i<len; i++)//计算斤
        {
            if(str[i]>='0' && str[i]<='9')
                jin = jin*10+str[i]-'0';
            else
                break;
        }
        jin = jin*0.5;//斤化为kg
        head = (int)jin;//取出整数部分
        t = jin - (int)jin;//小数部分保留在t中
        for(j = i; j<len; j++)//找出两
        {
            if(str[j]>='0' && str[j]<='9')
            {
                liang = str[j]-'0';
                break;
            }
        }
        liang*=0.05;//两化为kg
        t = t+liang;//这是整个kg的小数部分
        while(t - (int)t>1e-6)//将小数转化为整数
        {
            t*=10;
        }
        end = (int)t;
        printf("Case %d: ",cas++);
        if(end)
            printf("%d.%d\n",head,end);
        else
            printf("%d\n",head);
    }

    return 0;
}