STL algorithm算法any_of译文及使用（3）
std::any_of
template <class InputIterator, class UnaryPredicate>
bool any_of (InputIterator first, InputIterator last, UnaryPredicate pred);
true if pred returns true for any of the elements in the range [first,last), and false otherwise.如果范围内任一元素使pred返回true,则返回true,否则返回false.
例子：
#include <iostream>
#include <algorithm>
using namespace std;
bool isGreat(int i){
if(i>=5){
cout<<i<<">=5"<<" ,match!"<<endl;
return true;
}
else{
cout<<i<<"<5"<<" ,mismatch!"<<endl;
return false;
}
}
int main()
{
vector<int> vi{0,1,2,3,4,5,6};
if(any_of(vi.begin(),vi.end(),isGreat))
cout<<"Yes,some elements in vi >=5 "<<endl;
else
cout<<"no,all elements in vi didn't >=1 "<<endl;
cout<<endl;
int ar[5]={10,20,30,40,50};
if(any_of(ar,ar+5,[](int i){return i%10;}))
cout<<"some in ar can %10!=0"<<endl;
else
cout<<"all %10=0!"<<endl;
}运行截图：
If [first,last) is an empty range, the function returns false.
如果范围为空，则返回false.(因为没有任一匹配)
例子：
#include <iostream>
#include <algorithm>
using namespace std;
bool isGreat(int i){
if(i>=5){
cout<<i<<">=5"<<" ,match!"<<endl;
return true;
}
else{
cout<<i<<"<5"<<" ,mismatch!"<<endl;
return false;
}
}
int main()
{
vector<int> vi{0,1,2,3,4,5,6};
if(any_of(vi.begin(),vi.begin(),isGreat))
cout<<"emptiy=true "<<endl;
else
cout<<"emptiy=false "<<endl;
}
The behavior of this function template is equivalent to:
行为类似以下：
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Parameters
-
first, last
Input iterators to the initial and final positions in a sequence. The range used is
[first,last), which contains all theelements between first and last, including the element pointed by first but not the element pointed by last. -
标示序列范围的输入迭代器。包含了first,last之间的所有元素，包括first指向的元素，但不包括last.
pred
-
Unary function that accepts an element in the range as argument and returns a value convertible to
bool. The value returned indicates whether the element fulfills the condition checked by this function.
The function shall not modify its argument.
This can either be a function pointer or a function object.
-
一个接受一个元素类型参数并返回一个bool值的一元函数。
-
可以是一个指针或者函数对象。
-
Return value
true if pred returns true for any of the elements in the range [first,last), and false otherwise.如果任一的元素对pred的返回值是true，那么返回true,否则返回false.
[first,last) is an empty range, the function returns false.如果范围为空，则返回false.
Example
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Edit & Run
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Output:
There are negative elements in the range. |
Complexity
Up to linear in the distance between first and last: Calls pred for each element until a match is found.和first,last之间的距离线性相关，对每个元素调用pred直到一个匹配的值。
Data races
Some (or all) of the objects in the range[first,last) are accessed (once at most).最少一个元素被访问。
Exceptions
Throws if either pred or an operation on an iterator throws.Note that invalid parameters cause undefined behavior.
如果pred或者操作迭代器会抛出异常就会抛出异常。
无效的参数导致未定义的行为。
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转载请注明出处：http://blog.csdn.net/qq844352155
author:天下无双
Email:[email protected]
2014-9-1
于GDUT
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