STL algorithm算法count_if(11)

原文地址:http://www.cplusplus.com/reference/algorithm/count_if/

function template
<algorithm>

std::count_if

template <class InputIterator, class Predicate>
  typename iterator_traits<InputIterator>::difference_type
    count_if (InputIterator first, InputIterator last, UnaryPredicate pred);
Return number of elements in range satisfying condition
Returns the number of elements in the range [first,last) for which pred is true.
返回范围内对每个元素调用pred返回true的次数。
例子:
#include <iostream>
#include <algorithm>
#include <vector>
#include <array>
using namespace std;
bool ismod2(int i){
    return i%2==0;
}
void countif(){
    vector<int> vi{1,5,7,8,9,9,8,5,9};
    array<int,7> ai{888,666,555,222,111,555,777};
    cout<<"vi=";
    for(int &i:vi)
        cout<<i<<" ";
    cout<<endl;

    int cv=count_if(vi.begin(),vi.end(),ismod2);
    cout<<"能被2整除的一共有"<<cv<<"个"<<endl;

    cout<<"ai=";
    for(int &i:ai)
        cout<<i<<" ";
    cout<<endl;
    int ca=count_if(ai.begin(),ai.end(),[](int i){return i>500;});
    cout<<"大于500的一共有"<<ca<<"个"<<endl;




}
运行截图: STL algorithm算法count_if(11)_第1张图片


The behavior of this function template is equivalent to:
1 2 3 4 5 6 7 8 9 10 11 
template <class InputIterator, class UnaryPredicate> typename iterator_traits<InputIterator>::difference_type count_if (InputIterator first, InputIterator last, UnaryPredicate pred) { typename iterator_traits<InputIterator>::difference_type ret = 0; while (first!=last) { if (pred(*first)) ++ret; ++first; } return ret; }



Parameters

first, last
Input iterators to the initial and final positions of the sequence of elements. The range used is [first,last), which contains all the elements between first and last, including the element pointed by first but not the element pointed by last.
元素的范围。
pred
Unary function that accepts an element in the range as argument, and returns a value convertible to bool. The value returned indicates whether the element is counted by this function.
The function shall not modify its argument.
This can either be a function pointer or a function object.
接受一个元素作为参数兵返回一个bool值的一元函数。

Return value

The number of elements in the range [first,last) for which pred does not return false.
The return type (iterator_traits<InputIterator>::difference_type) is a signed integral type.
返回范围内对每个元素调用pred返回true的次数。


Example

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 
// count_if example #include <iostream> // std::cout #include <algorithm> // std::count_if #include <vector> // std::vector bool IsOdd (int i) { return ((i%2)==1); } int main () { std::vector<int> myvector; for (int i=1; i<10; i++) myvector.push_back(i); // myvector: 1 2 3 4 5 6 7 8 9 int mycount = count_if (myvector.begin(), myvector.end(), IsOdd); std::cout << "myvector contains " << mycount << " odd values.\n"; return 0; }
Edit & Run


Output:
myvector contains 5 odd values. 

Complexity

Linear in the distance between first and last: Calls pred once for each element.

Data races

The objects in the range [first,last) are accessed (each object is accessed exactly once).

Exceptions

Throws if pred trhows or if any of the operations on iterators throws.
Note that invalid arguments cause undefined behavior.

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//写的错误或者不好的地方请多多指导,可以在下面留言或者点击左上方邮件地址给我发邮件,指出我的错误以及不足,以便我修改,更好的分享给大家,谢谢。

转载请注明出处:http://blog.csdn.net/qq844352155

author:天下无双

Email:[email protected]

2014-9-11

于GDUT

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