HIT OJ 1087 哈工大OJ

 

Self Numbers

	Source : ACM ICPC Mid-Central USA 1998
	Time limit : 5 sec		Memory limit : 32 M

Submitted : 1119, Accepted : 448

In 1949 the Indian mathematician D.R. Kaprekar discovered a class of numbers called self-numbers. For any positive integer n, define d(n) to be n plus the sum of the digits of n. (The d stands for digitadition, a term coined by Kaprekar.) For example, d(75) = 75 + 7 + 5 = 87. Given any positive integer n as a starting point, you can construct the infinite increasing sequence of integers n, d(n), d(d(n)), d(d(d(n))), .... For example, if you start with 33, the next number is 33 + 3 + 3 = 39, the next is 39 + 3 + 9 = 51, the next is 51 + 5 + 1 = 57, and so you generate the sequence

33, 39, 51, 57, 69, 84, 96, 111, 114, 120, 123, 129, 141, ...

The number n is called a generator of d(n). In the sequence above, 33 is a generator of 39, 39 is a generator of 51, 51 is a generator of 57, and so on. Some numbers have more than one generator: for example, 101 has two generators, 91 and 100. A number with no generators is a self-number. There are thirteen self-numbers less than 100: 1, 3, 5, 7, 9, 20, 31, 42, 53, 64, 75, 86, and 97.

Write a program to output all positive self-numbers less than or equal 1000000 in increasing order, one per line.

Sample Output

1
3
5
7
9
20
31
42
53
64
|
| <-- a lot more numbers
|
9903
9914
9925
9927
9938
9949
9960
9971
9982
9993
|
|
|

筛选法。剪下枝就OK

 

水题哈

#include<stdio.h>
#include<algorithm>
#include<string.h>

using namespace std;

bool flag[1000005];

int cal(int n)
{
	int ret=n;
	while(n)
	{
		ret=ret+(n%10);
		n=n/10;
	}
	return ret;
}

void init()
{
	int i,next;
	for(i=1;i<=1000000;i++)
	{
		if(!flag[i])
		{
			printf("%d\n",i);
			next=cal(i);
			while(next<=1000000)
			{
				if(flag[next])
					break;
				flag[next]=true;
				next=cal(next);
			}
		}
	}
}

int main()
{
	int i;
	init();
	return 0;
}