HDU2952：Counting Sheep(DFS)

Problem Description

A while ago I had trouble sleeping. I used to lie awake, staring at the ceiling, for hours and hours. Then one day my grandmother suggested I tried counting sheep after I'd gone to bed. As always when my grandmother suggests things, I decided to try it out. The only problem was, there were no sheep around to be counted when I went to bed.


Creative as I am, that wasn't going to stop me. I sat down and wrote a computer program that made a grid of characters, where # represents a sheep, while . is grass (or whatever you like, just not sheep). To make the counting a little more interesting, I also decided I wanted to count flocks of sheep instead of single sheep. Two sheep are in the same flock if they share a common side (up, down, right or left). Also, if sheep A is in the same flock as sheep B, and sheep B is in the same flock as sheep C, then sheeps A and C are in the same flock.


Now, I've got a new problem. Though counting these sheep actually helps me fall asleep, I find that it is extremely boring. To solve this, I've decided I need another computer program that does the counting for me. Then I'll be able to just start both these programs before I go to bed, and I'll sleep tight until the morning without any disturbances. I need you to write this program for me.

 

Input

The first line of input contains a single number T, the number of test cases to follow.

Each test case begins with a line containing two numbers, H and W, the height and width of the sheep grid. Then follows H lines, each containing W characters (either # or .), describing that part of the grid.

 

Output

For each test case, output a line containing a single number, the amount of sheep flock son that grid according to the rules stated in the problem description.

Notes and Constraints
0 < T <= 100
0 < H,W <= 100

 

Sample Input

   
   
   
   

    
    
    
    2
4 4
#.#.
.#.#
#.##
.#.#
3 5
###.#
..#..
#.###
   
   
   
   

 

Sample Output

   
   
   
   

    
    
    
    6
3
   
   
   
   

 

 

简单深搜，就是把1241的代码稍微改下就可以了

 

#include <stdio.h>
#include <string.h>
char map[105][105],mat[105][105];
int vis[105][105];

void dfs(int i,int j)
{
    if(vis[i][j] || mat[i][j] == '.')
    return ;
    vis[i][j] = 1;
    dfs(i-1,j);
    dfs(i,j-1);
    dfs(i,j+1);
    dfs(i+1,j);
}

int main()
{
    int n,m,t;
    scanf("%d",&t);
    while(t--)
    {
        scanf("%d%d%*c",&n,&m);
        memset(map,0,sizeof(map));
        memset(mat,'.',sizeof(mat));
        memset(vis,0,sizeof(vis));
        int i,j,cnt = 0;
        if(!m&&!n)
        break;
        for(i = 0;i<n;i++)
        {
            for(j = 0;j<m;j++)
            {
                scanf("%c",&map[i][j]);
                mat[i+1][j+1] = map[i][j];
            }
            getchar();
        }
        for(i = 1 ;i<=n;i++)
        {
            for(j = 1;j<=m;j++)
            {
                if(!vis[i][j] && mat[i][j] == '#')
                {
                    dfs(i,j);
                    cnt++;
                }
            }
        }
        printf("%d\n",cnt);
    }
    return 0;
}