Leetcode习题: SingleNumber II

Single Number II

 
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Given an array of integers, every element appears three times except for one. Find that single one.

Note:
Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?

看有做法采用一个33位的数组来保存每一bit上3的次数,然后每次模3以满3时清零。然而这其实不满足题目"without using extra memory"的要求。还是搜索到了一种更为巧妙的解法。

public class Solution {
  
    /**
     * 其中ones记录了所有出现了模3余1次的bit,twos记录的是余2的。not_threes是当一个bit出现第3次的时候,把它清掉。
     * 最后输出ones(如果题目中那个特殊的数出现了1次,当然如果是出现2次的话,应该输出twos
     * 
     * @param A
     * @return
     */
    public int singleNumber(int[] A) {
        int once = 0;
        int twice = 0;


        for (int i = 0; i < A.length; i++) {
            twice |= once & A[i];
            once ^= A[i];
            int not_three = ~(once & twice);
            once = not_three & once;
            twice = not_three & twice;
        }
        return once;
    }
}


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