[欧拉回路] poj 2513 Colored Sticks

题目链接：

http://poj.org/problem?id=2513

Colored Sticks Time Limit: 5000MS   Memory Limit: 128000K Total Submissions: 30955   Accepted: 8159 Description You are given a bunch of wooden sticks. Each endpoint of each stick is colored with some color. Is it possible to align the sticks in a straight line such that the colors of the endpoints that touch are of the same color? Input Input is a sequence of lines, each line contains two words, separated by spaces, giving the colors of the endpoints of one stick. A word is a sequence of lowercase letters no longer than 10 characters. There is no more than 250000 sticks. Output If the sticks can be aligned in the desired way, output a single line saying Possible, otherwise output Impossible. Sample Input blue red red violet cyan blue blue magenta magenta cyan Sample Output Possible Hint Huge input,scanf is recommended. Source The UofA Local 2000.10.14

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题目意思：

有n条木棒，每条木棒两端有两种颜色，求这些木棒能否能在一起，使得前一个木棒的后端颜色和前一个木棒的前端颜色一样。

解题思路：

欧拉通路+字典树+并查集

注意是无向边，注意要判断连通性，直接用map映射会超时，自己写字典树。

代码：

//#include<CSpreadSheet.h>

#include<iostream>
#include<cmath>
#include<cstdio>
#include<sstream>
#include<cstdlib>
#include<string>
#include<string.h>
#include<cstring>
#include<algorithm>
#include<vector>
#include<map>
#include<set>
#include<stack>
#include<list>
#include<queue>
#include<ctime>
#include<bitset>
#include<cmath>
#define eps 1e-6
#define INF 0x3f3f3f3f
#define PI acos(-1.0)
#define ll __int64
#define LL long long
#define lson l,m,(rt<<1)
#define rson m+1,r,(rt<<1)|1
#define M 1000000007
//#pragma comment(linker, "/STACK:1024000000,1024000000")
using namespace std;

#define Maxn 550000

int dei[Maxn],a[Maxn],cnt,la;

struct Node
{
    struct Node * next[30];
    int nu;
}node[Maxn*15],root;


int Insert(char *a)
{
    Node * p=&root;

    while(*a)
    {
        if(p->next[*a-'a'+1]==NULL)
        {
            node[++la].nu=0;
            memset(node[la].next,NULL,sizeof(node[la].next));
            p->next[*a-'a'+1]=&node[la];
        }
        p=p->next[*a-'a'+1];
        a++;
    }
    if(!p->nu)
        p->nu=++cnt;
    return p->nu;

}

int Find(int x)
{
    int temp=x;
    while(x!=fa[x])
        x=fa[x];
    while(fa[temp]!=x)
    {
        int cur=fa[temp];
        fa[temp]=x;
        temp=cur;
    }
    return x;
}
void Unio(int a,int b)
{
    a=Find(a),b=Find(b);
    if(a!=b)
        fa[a]=b;
}
int main()
{

   memset(dei,0,sizeof(dei));
   string a,b;
   char sa[15],sb[15];
   cnt=la=0;
   for(int i=1;i<=Maxn-5000;i++)
        fa[i]=i;

   memset(root.next,NULL,sizeof(root.next));
   root.nu=0;

   while(~scanf("%s%s",sa+1,sb+1))
   {
       int a=Insert(sa+1);
       int b=Insert(sb+1);

       dei[a]++,dei[b]++;
       Unio(a,b);
   }
   bool ans=true;
   int nui=0,nuo=0,la=-1;

   for(int i=1;i<=cnt;i++)
   {
       if(la==-1)
            la=Find(i);
       else if(la!=Find(i))
       {
           ans=false;
           break;
       }
       if(dei[i]&1)
            nui++;
   }
   if(!ans||nui>2||nui==1)
        printf("Impossible\n");
   else
        printf("Possible\n");
   //system("pause");

    return 0;
}