SQLiteException: bind or column index out of range

今天写一个登录的时候查询数据库时报了这样的错误

出错代码：

	private PhoneNumber queryPhone(String phonenumber) {
		SQLiteDatabase sqLiteDatabase = DB.getWritableDatabase();
		PhoneNumber phoneNumber = new PhoneNumber();
		Cursor cursor = sqLiteDatabase.query("PhoneNumber", new String[] {
				"id", "phonenumber", "passwd", "username" }, "phonenumber",
				new String[] { phonenumber }, null, null, null);
		while (cursor.moveToNext()) {
			phoneNumber.id = cursor.getInt(cursor.getColumnIndex("id"));
			phoneNumber.phoneNumber = cursor.getString(cursor
					.getColumnIndex("phonenumber"));
			phoneNumber.passwd = cursor.getString(cursor
					.getColumnIndex("passwd"));
			phoneNumber.username = cursor.getString(cursor.getColumnIndex("username"));
		}
		DB.close();
		sqLiteDatabase.close();
		return phoneNumber;
	}

查询条件忘记加“=？”了

改正之后代码：

	private PhoneNumber queryPhone(String phonenumber) {
		SQLiteDatabase sqLiteDatabase = DB.getWritableDatabase();
		PhoneNumber phoneNumber = new PhoneNumber();
		Cursor cursor = sqLiteDatabase.query("PhoneNumber", new String[] {
				"id", "phonenumber", "passwd", "username" }, "phonenumber=?",
				new String[] { phonenumber }, null, null, null);
		while (cursor.moveToNext()) {
			phoneNumber.id = cursor.getInt(cursor.getColumnIndex("id"));
			phoneNumber.phoneNumber = cursor.getString(cursor
					.getColumnIndex("phonenumber"));
			phoneNumber.passwd = cursor.getString(cursor
					.getColumnIndex("passwd"));
			phoneNumber.username = cursor.getString(cursor.getColumnIndex("username"));
		}
		DB.close();
		sqLiteDatabase.close();
		return phoneNumber;
	}

这样就对了 记录下 下次不要犯这样的错误