//竖式问题 #include<stdio.h> #include<string.h> int main(){ int i,ok,abc,de,x,y,z,count=0; char s[20],buf[99]; scanf("%s",s); for(abc=111;abc<=999;abc++) for(de=11;de<=99;de++){ x=abc*(de%10);//计算abc*e的值并赋给x y=abc*(de/10);//计算abc*d的值并赋给y z=abc*de; //printf输出到屏幕,fprintf输出到文件,sprintf输出到字符串 sprintf(buf,"%d%d%d%d%d",abc,de,x,y,z); ok=1; for(i=0;i<strlen(buf);i++) if(strchr(s,buf[i])==NULL) ok=0; if(ok){ printf("<%d>\n",++count); printf("%5d\nX%4d\n-----\n%5d\n%4d\n-----\n%5d\n\n",abc,de,x,y,z); } } printf("The number of solutions =%d\n",count); return 0; }
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函数名: sprintf #include <stdio.h> int main(void) sprintf(buffer, "An approximation of Pi is %f\n", M_PI); |