hdu2952（Counting Sheep ）

点击打开链接

Problem Description

A while ago I had trouble sleeping. I used to lie awake, staring at the ceiling, for hours and hours. Then one day my grandmother suggested I tried counting sheep after I'd gone to bed. As always when my grandmother suggests things, I decided to try it out. The only problem was, there were no sheep around to be counted when I went to bed.


Creative as I am, that wasn't going to stop me. I sat down and wrote a computer program that made a grid of characters, where # represents a sheep, while . is grass (or whatever you like, just not sheep). To make the counting a little more interesting, I also decided I wanted to count flocks of sheep instead of single sheep. Two sheep are in the same flock if they share a common side (up, down, right or left). Also, if sheep A is in the same flock as sheep B, and sheep B is in the same flock as sheep C, then sheeps A and C are in the same flock.


Now, I've got a new problem. Though counting these sheep actually helps me fall asleep, I find that it is extremely boring. To solve this, I've decided I need another computer program that does the counting for me. Then I'll be able to just start both these programs before I go to bed, and I'll sleep tight until the morning without any disturbances. I need you to write this program for me.

 

Input

The first line of input contains a single number T, the number of test cases to follow.

Each test case begins with a line containing two numbers, H and W, the height and width of the sheep grid. Then follows H lines, each containing W characters (either # or .), describing that part of the grid.

 

Output

For each test case, output a line containing a single number, the amount of sheep flock son that grid according to the rules stated in the problem description.

Notes and Constraints
0 < T <= 100
0 < H,W <= 100

 

Sample Input

   
   
   
   

    
    
    
    2
4 4
#.#.
.#.#
#.##
.#.#
3 5
###.#
..#..
#.###
   
   
   
   

 

Sample Output

   
   
   
   

    
    
    
    6
3
   
   
   
   

#include<stdio.h>
#include<string.h>
char aa[200][200];
int visit[105][105],w,h;
int s[4][2]={{1, 0}, {0, -1}, { -1, 0}, {0, 1}};
int DFS(int a,int b)
{
    int i,x,y;
    for(i=0;i<4;i++)
    {
        x=a+s[i][0];
        y=b+s[i][1];
        if(visit[x][y]==0&&x>=0&&x<h&&y>=0&&y<w&&aa[x][y]=='#')
        {
            visit[x][y]=1;
            DFS(x,y);
        }
    }
}
int main()
{
    int t,i,j,c,d,count;
    scanf("%d",&t);
    while(t--)
    {
        count=0;
        memset(visit,0,sizeof(visit));
        scanf("%d %d",&h,&w);
        getchar();
        for(i=0;i<h;i++)
        gets(aa[i]);
        for(i=0;i<h;i++)
        for(j=0;j<w;j++)
        {
            if(aa[i][j]=='#'&&visit[i][j]==0)
            {
                visit[i][j]=1;
                DFS(i,j);
                count++;
            }
        }
        printf("%d\n",count);
    }
    return 0;
}