hdu 5347 MZL's chemistry 2015多校联合训练赛#5 打表

MZL's chemistry

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)
Total Submission(s): 385    Accepted Submission(s): 314

Problem Description

MZL define  F(X)  as the first ionization energy of the chemical element  X

Now he get two chemical elements  U,V ,given as their atomic number,he wants to compare  F(U)  and  F(V)

It is guaranteed that atomic numbers belongs to the given set: {1,2,3,4,..18,35,36,53,54,85,86}

It is guaranteed the two atomic numbers is either in the same period or in the same group

It is guaranteed that  x≠y

 

Input

There are several test cases

For each test case,there are two numbers  u,v ,means the atomic numbers of the two element

 

Output

For each test case,if  F(u)>F(v) ,print "FIRST BIGGER",else print"SECOND BIGGER"

 

Sample Input

   
   
   
   

    
    
    
    1 2
5 3
   
   
   
   

 

Sample Output

   
   
   
   

    
    
    
    SECOND BIGGER
FIRST BIGGER
   
   
   
   

 

Source

2015 Multi-University Training Contest 5

 

百度，直接打表输出

#include<iostream>
#include<cstring>
#include<algorithm>
#include<cstdio>
using namespace std;

double res[100]={
0,
1312.0,
2372.3,
520.2,
899.5,
800.6,
1086.5,
1402.3,
1313.9,
1681.0,
2080.7,
495.8,
737.7,
577.5,
786.5,
1011.8,
999.6,
1251.2,
1520.6

};


int main(){
    int n,m;
    res[35] = 1139.9;
    res[36] = 1350.8;
    res[53] = 1008.4;
    res[54] = 1170.4;
    res[85] = 890;
    res[86] = 1037;
    while(cin>>n>>m){
        if(res[n] > res[m]) puts("FIRST BIGGER");
        else puts("SECOND BIGGER");
    }
    return 0;
}