广义表建树

简单的广义表建树,但是却纠结了几个小时,总之是太囧了。。。代码还很糟糕。。。

不过也记录一下,或许以后还是用得上。

殷人昆数据结构 5.37 题

代码:

#include <iostream>
using namespace std;

#define ADD 5

struct treeNode
{
	char val;
	treeNode * son, * next;
};

bool isLetter(char a)
{
	return ( ( a >= 'a' && a <= 'z' ) || ( a >= 'A' && a <= 'Z' ) );
}

void buildTree(treeNode * root, char array[], int & id, int len)
{
	id++;
	if( id >= len || array[id] == ',' || array[id] == ')'  ) { 
         root->son = NULL; return; 
	}
	
	treeNode * last = NULL;
	treeNode * newNode;
	while(id < len && array[id] != ')')
	{
		if( isLetter(array[id]) ) { 
			newNode = new treeNode;
			newNode->val = array[id];
			newNode->next = NULL;
			if( last == NULL )
				root->son = newNode;
			else last->next = newNode;
			last = newNode;
			buildTree(newNode, array, id, len);
		}
		else id++;
	}
	id++;
}

void convert(treeNode * root, int len)
{
    if( root == NULL ) return;
	
	for( int i = 1; i <= len; i++) cout << " ";
    cout << root->val << endl;
	convert(root->son, len + ADD);
	convert(root->next, len);
}


int main()
{
    char tree[] = "A(B(C,D),E(F(G,H),I,J),K)";
    int id;
	treeNode * root = new treeNode;
	root->val = tree[0];
	root->next = NULL;
	id = 0;
	buildTree(root, tree, id, strlen(tree));
	convert(root, 0);
	
	return 0;
}


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