我和秦冰超一组。秦冰超的博客地址 http://www.cnblogs.com/qinxian0/
设计思路:1.将题目的难度属性放在数组中,并赋予初值。
2.定义四则运算的数据结构。
3.利用链表判断题目是否重复。
4.调用jisuan.h中的answer判断答案是否正确
5.利用rand%4函数表示运算符。0+,1-,2*,3/
#include<iostream> #include "stdlib.h" #include "time.h" #include "jisuan.h" #include "iomanip" using namespace std; //判断回答是否正确 bool YorN(jisuan &Q, int answer) { if (Q.yunsuanfu == 0)//yunsaunfu为运算符0+,1-,2*,3/ { Q.answer = Q.num1 + Q.num2; } else if (Q.yunsuanfu == 1) { Q.answer = Q.num1 - Q.num2; } else if (Q.yunsuanfu == 2) { Q.answer = Q.num1*Q.num2; } else Q.answer = Q.num1 / Q.num2; if (answer == Q.answer) return true; else return false; } //生成算术题 void Build(jisuan &Q) { if (tideshuxing[2] == 1)//有乘除 Q.yunsuanfu = rand() % 4; else//没有乘除 Q.yunsuanfu = rand() % 2; Q.num1 = rand() % (tideshuxing[4] - tideshuxing[3] + 1) + tideshuxing[3];//生成在取值范围间的随机数 Q.num2 = rand() % (tideshuxing[4] - tideshuxing[3] + 1) + tideshuxing[3]; } //输出函数 void Display1(LinkC C, jisuan &Q) { int temp, count = 0; //count记录重新生成题目的次数 for (int i = 1; i <= tideshuxing[1]; i++) { cout << "(" << i << ")"; if (tideshuxing[2] == 1) Q.yunsuanfu = rand() % 4; else Q.yunsuanfu = rand() % 2; Q.num1 = rand() % (tideshuxing[4] - tideshuxing[3] + 1) + tideshuxing[3]; Q.num2 = rand() % (tideshuxing[4] - tideshuxing[3] + 1) + tideshuxing[3]; RB: Build(Q); //检查是否有重复的题目 switch (Q.yunsuanfu) { case 0: if (ExistQues(C, Q))//调用jisuan.h中的ExistQues { count++; goto RB; } cout << Q.num1 << "+" << Q.num2 << "=" << setw(5); break; case 1: if ((tideshuxing[5] == 0) && (Q.num1<Q.num2))//若为负数,则交换 { temp = Q.num1; Q.num1 = Q.num2; Q.num2 = temp; } if (ExistQues(C, Q)) { count++; goto RB; } cout << Q.num1 << "-" << Q.num2 << "=" << setw(5); break; case 2: if (ExistQues(C, Q)) { count++; goto RB; } cout << Q.num1 << "*" << Q.num2 << "=" << setw(5); break; case 3: while (Q.num2 == 0) Q.num2 = rand() % (tideshuxing[4] - tideshuxing[3] + 1) + tideshuxing[3]; if (!tideshuxing[6]) { while ((Q.num1%Q.num2) != 0 || Q.num2 == 0) { //重新生成 Q.num1 = rand() % (tideshuxing[4] - tideshuxing[3] + 1) + tideshuxing[3]; Q.num2 = rand() % (tideshuxing[4] - tideshuxing[3] + 1) + tideshuxing[3]; } } if (ExistQues(C, Q)) { count++; goto RB; } cout << Q.num1 << "/" << Q.num2 << "=" << setw(5); break; } InsertQues(C, Q); if (i%tideshuxing[2] == 0) //一行打印完规定列数,换行 for (int j = 0; j <= tideshuxing[3]; j++) cout << endl; } cout << endl << endl; } //回答题目函数 void Display2(LinkC C, jisuan &Q) { int temp, count = 0, answer = 0, right = 0; //count记录重新生成题目的次数 for (int i = 1; i <= tideshuxing[1]; i++) { cout << "(" << i << ")"; if (tideshuxing[2] == 1) Q.yunsuanfu = rand() % 4; else Q.yunsuanfu = rand() % 2; Q.num1 = rand() % (tideshuxing[4] - tideshuxing[3] + 1) + tideshuxing[3]; Q.num2 = rand() % (tideshuxing[4] - tideshuxing[3] + 1) + tideshuxing[3]; RB: Build(Q); //检查是否有出过的题目 switch (Q.yunsuanfu) { case 0: if (ExistQues(C, Q)) { count++; goto RB; } cout << Q.num1 << "+" << Q.num2 << "="; cin >> answer; if (YorN(Q, answer)) { cout << "\t正确"; right++; } else cout << "\t错误"; break; case 1: if ((tideshuxing[5] == 0) && (Q.num1<Q.num2))//若为负数,则交换 { temp = Q.num1; Q.num1 = Q.num2; Q.num2 = temp; } if (ExistQues(C, Q)) { count++; goto RB; } cout << Q.num1 << "-" << Q.num2 << "="; cin >> answer; if (YorN(Q, answer)) { cout << "\t正确"; right++; } else cout << "\t错误"; break; case 2: if (ExistQues(C, Q)) { count++; goto RB; } cout << Q.num1 << "*" << Q.num2 << "="; cin >> answer; if (YorN(Q, answer)) { cout << "\t正确"; right++; } cout << "\t错误"; break; case 3: while (Q.num2 == 0)//被除数不能为0 Q.num2 = rand() % (tideshuxing[4] - tideshuxing[3] + 1) + tideshuxing[3]; if (!tideshuxing[6]) { while ((Q.num1%Q.num2) != 0 || Q.num2 == 0) //重新生成 { Q.num1 = rand() % (tideshuxing[4] - tideshuxing[3] + 1) + tideshuxing[3]; Q.num2 = rand() % (tideshuxing[4] - tideshuxing[3] + 1) + tideshuxing[3]; } } if (ExistQues(C, Q)) { count++; goto RB; } cout << Q.num1 << "/" << Q.num2 << "="; cin >> answer; if (YorN(Q, answer)) { cout << "\t正确"; right++; } cout << "\t错误"; break; } InsertQues(C, Q); cout << endl; } cout << "共回答正确" << right << "道题。"; cout << endl << endl; } //判断难度 void YesOrNo(int tideshuxing) { if (tideshuxing) cout << "是"; else cout << "否"; } //判断输入是否正确 void Reset(int i) { do { cout << "请重新设置(是1/否0):"; cin >> tideshuxing[i]; } while (tideshuxing[i] != 0 && tideshuxing[i] != 1); } //设置题目难度 void SetLevel() { system("cls"); char move2; cout << "\t/*************设置题目难度*************/" << endl; cout << "\t 0.是否有乘除法("; YesOrNo(tideshuxing[2]); cout << ")" << endl; cout << "\t 1.数值范围(" << tideshuxing[3] << "~" << tideshuxing[4] << ")" << endl; cout << "\t 2.是否有负数("; YesOrNo(tideshuxing[5]); cout << ")" << endl; cout << "\t 3.是否有余数("; YesOrNo(tideshuxing[6]); cout << ")" << endl; cout << "\t 4.返回主菜单" << endl; cout << "\t/**************************************/" << endl; cout << "请选择后续操作(0~4):"; cin >> move2; while (move2<'0' || move2>'4') { cout << "错误!请正确输入操作序号(0~4):"; cin >> move2; } switch (move2) { case '0':Reset(4); break; case '1': reset1 : cout << "新的数值下限:"; cin >> tideshuxing[3]; cout << "新的数值上限:"; cin >> tideshuxing[4]; if (tideshuxing[3] >= tideshuxing[4]) { cout << "出错!请重新输入数值范围!" << endl; goto reset1; } break; case '2':Reset(7); break; case '3':Reset(8); break; case '4':break; } } //主页面 void MainMenu(LinkC &C, jisuan &Q) { char move, save; cout << "\t 0.输入出题数量" << endl; cout << "\t 1.设置题目难度" << endl; cout << "\t 2.开始出题" << endl; cout << "\t 3.开始答题" << endl; cout << "\t 4.退出系统" << endl; cout << "请选择后续操作(0~4):"; cin >> move; while (move<'0' || move>'4') { cout << "错误!请正确输入操作序号(0~4):"; cin >> move; } switch (move) { case '2':Display1(C, Q); break; case '0': reset4 : cout << "请设置出题数量:"; cin >> tideshuxing[1]; if (tideshuxing[1] <= 0) { cout << "出错!请重新输入!" << endl; goto reset4; } break; case '1':SetLevel(); break; case '3':Display2(C, Q); break; case '4': cout << "是否保存出题记录(是1/否0):"; cin >> save; while (save != '1'&&save != '0') { cout << "出错!请正确输入(是1/否0):"; cin >> save; } if (save == '1') WriteQues(C);//调用jisuan.h中的WriteQues cout << "感谢您的使用,再见!" << endl; tideshuxing[0] = 0; break; } } int main(int argc, char* argv[]) { srand((unsigned)time(NULL)); //srand()函数产生一个以当前时间开始的随机种子 LinkC Cacu; jisuan ques; InitList(Cacu); ReadQues(Cacu); while (tideshuxing[0]) { system("cls"); MainMenu(Cacu, ques); system("pause"); } return 0; } //jisuan.h #include<iostream> #include <fstream> using namespace std; int tideshuxing[10] = { 1, 30, 0, 0, 5, 0, 0, 0 }; //将题的属性放在数组中,并赋予初值。0退出、1出题数量、2乘除、3数值范围下限、4数值范围上限、5负数、6余数、7出过的题目数 //四则算术题的数据结构 typedef struct { int num1; int num2; int yunsuanfu; int answer; }jisuan; typedef struct CNode //结点 { jisuan ques; struct CNode * next; }CNode, *LinkC; //题目初始化 void InitList(LinkC &C) { C = new CNode; C->next = NULL; } //添加题目信息 void InsertQues(LinkC &C, jisuan Q) {//尾插入 LinkC tail, temp; tail = C; while (tail&&tail->next != NULL) tail = tail->next; temp = new CNode; temp->ques = Q; temp->next = NULL; tail->next = temp; tail = temp; tideshuxing[9]++; } //判断题目存在 int ExistQues(LinkC C, jisuan Q) { LinkC temp; temp = C->next; while (temp) { if ((temp->ques.num1 == Q.num1) && (temp->ques.num2 == Q.num2) && (temp->ques.yunsuanfu == Q.yunsuanfu)) return 1; //当两个数字和算符与链表中的一样,则存在 else temp = temp->next; } return 0; } //读取出过的问题 void ReadQues(LinkC &C) { LinkC temp; ifstream infile("question.txt"); for (int i = 0; i<10; i++) //读取参数表 infile >> tideshuxing[i]; for (int i = 0; i<tideshuxing[9]; i++) //读取出过的题目 { temp = new CNode; infile >> temp->ques.num1; infile >> temp->ques.num2; infile >> temp->ques.yunsuanfu; temp->next = NULL; } } //保存到txt void WriteQues(LinkC C) { LinkC temp; ofstream outfile("question.txt"); if (!outfile) { cout << "文件存储失败!" << endl; exit(0); } for (int i = 0; i<10; i++) outfile << tideshuxing[i] << " "; for (temp = C->next; temp; temp = temp->next) { outfile << temp->ques.num1 << " "; outfile << temp->ques.num2 << " "; outfile << temp->ques.yunsuanfu << " "; } }
项目计划总结:
项目计划总结:
日期 | 开始时间 | 中断事件 | 中断事件 | 净时间 | 活动 |
3/14 | 14:00 | 15:50 | 10分钟 | 100分钟 | 上课 |
16:30 | 17:30 | 0 | 60分钟 | 写作业 | |
3/15 | 13:00 | 14:30 | 0 | 90分钟 | 写作业 |
3/16 | 15:00 | 16:00 | 0 | 60分钟 | 写作业 |
3/17 | 15:00 | 16:00 | 0 | 60分钟 | 写作业 |
3/18 | 14:00 | 15:00 | 0 | 60分钟 | 写作业 |
日期&&任务 | 听课 | 编写程序 | 阅读相关书籍 | 网上查找资料 | 日总结 |
周一 | 2H | 2H | 0H | 0.5H | 4.5H |
周二 | 1H | 0.5H | 0.5H | 2H | |
周三 | 2H | 1H | 0.5H | 3.5H | |
周四 | 2H | 0H | 0H | 0H | 2H |
周五 | 3H | 1H | 1H | 5H | |
周六 | 4H | 2H | 2H | 8H | |
周日 | 0H | 0H | 0H | 0H | |
周总结 | 4H | 12H | 4.5H | 4.5H | 25H |
缺陷记录日志:在这次结对编程汇中,我没有很好地适应结对训练,在开发中,对数据结构这一部分不是很熟悉。