【C++】PAT（advanced level)1065. A+B and C (64bit) (20)

1065. A+B and C (64bit) (20)

时间限制

100 ms

内存限制

32000 kB

代码长度限制

16000 B

判题程序

Standard

作者

HOU, Qiming

Given three integers A, B and C in [-2⁶³, 2⁶³], you are supposed to tell whether A+B > C.

Input Specification:

The first line of the input gives the positive number of test cases, T (<=10). Then T test cases follow, each consists of a single line containing three integers A, B and C, separated by single spaces.

Output Specification:

For each test case, output in one line "Case #X: true" if A+B>C, or "Case #X: false" otherwise, where X is the case number (starting from 1).

Sample Input:

3
1 2 3
2 3 4
9223372036854775807 -9223372036854775808 0

Sample Output:

Case #1: false
Case #2: true
Case #3: false

a 参考了http://tech-wonderland.net/blog/pat-1065-ab-and-c-64bit.html

//一个是LLONG_MAX  #include <climits> 

#include<iostream>
#include<string>
#include<climits>
using namespace std;


int main()
{	int n,m;
	long long int  a,b,c;
	while(cin>>n){
		m=n;
		//cout<<LLONG_MAX;
		while(m--){
			cin>>a>>b>>c;
			if(a>LLONG_MAX-b&&a>0&&b>0){//a+b超过 
				cout<<"Case #"<<n-m<<": true"<<endl;
			}else if(a<LLONG_MIN-b&&a<0&&b<0){
				cout<<"Case #"<<n-m<<": false"<<endl;
			}else if(a+b>c){
				cout<<"Case #"<<n-m<<": true"<<endl;
			}else {
				cout<<"Case #"<<n-m<<": false"<<endl;
			}

		}
		
	}
	return 0;
}