udt-问题解决

Q:
when my client computers connect server, 1 or 2 computers always 
say "abort for security reasons". 
i cannot find any firewall in the computer,and other computer is right.
please do me a favor, what reason is it?
thanks for your help!

W:
The only reason to cause this error is that the client received a wrong response 
from the server. The response UDP packet may be changed or damaged somewhere in 
the middle.


解决:
之前的包头说明：key为随机的四子节秘钥
#pragma  pack(1) 
struct UDPHead{
char  flag;
short bodylen;
    char  key[4]; //now used 4 bytes
char  other[9];
};
#pragma  pack() 


core.cpp
void CUDT::connect(const sockaddr* serv_addr)
中
int CHandShake::serialize(char* buf, int& size)


udt数据是head+data
int32_t m_iVersion;          // UDT version
int32_t m_iType;             // UDT socket type 
int32_t m_iISN;              // random initial sequence number
int32_t m_iMSS;              // maximum segment size
int32_t m_iFlightFlagSize;   // flow control window size
int32_t m_iReqType;          // connection request type: 1: regular connection request, 0: rendezvous connection request, -1/-2: response
int32_t m_iID; // socket ID
int32_t m_iCookie; // cookie
uint32_t m_piPeerIP[4]; // The IP address that the peer's UDP port is bound to

该函数中发送包之后会接收对方的数据包则调用

int CUDT::connect(const CPacket& response) throw (){

if ((1 != response.getFlag()) || (0 != response.getType()))
      return -1;

}

就相当于A主动去connect B，而B用UDP发来个不符合要求的数据包，这样就冲突了，悲剧了。

因此前8字节最好别动，因为存在m_iType，所以改后的数据包为
#pragma  pack(1) 
struct UDPHead{
char  flag;
short bodylen;
char  other[9];
char  key[4]; //now used 4 bytes
};
#pragma  pack()