hdu 3346

水题，太简单了，就是写代码，想都不用想

Problem Description

To Chinese people, 8 is a lucky number. Now your task is to judge if a number is lucky.
We say a number is lucky if it’s a multiple of 8, or the sum of digits that make up the number is a multiple of 8, or the sum of every digit’s square is a multiple of 8.

 

 

Input

The first line contains an integer stands for the number of test cases.
Each test case contains an integer n (n >= 0).

 

 

Output

For each case, output “Lucky number!” if the number is lucky, otherwise output “What a pity!”.

 

 

Sample Input

   
   
   
   

    
    
    
    2
0
8
   
   
   
   

 

 

Sample Output

   
   
   
   

    
    
    
    Lucky number!
Lucky number!
   
   
   
   
   
   
   
   

    
    
    
    source code：
   
   
   
   
   
   
   
   

    
    
    
    #include<iostream>
#include<cstdlib>
using namespace std;
int main()
{
    int n,m,sum1,sum2;
    cin>>n; 
    while(n--)
    {
    cin>>m;
    sum1=0;
    sum2=0;
    if(m%8==0)
    {cout<<"Lucky number!"<<endl;}
    else
    {
    while(m)
    {
    sum1+=m%10;
    sum2+=(m%10)*(m%10);
    m=m/10;
    }
    if(sum1%8==0||sum2%8==0)
    cout<<"Lucky number!"<<endl;
    else
    cout<<"What a pity!"<<endl;
    }
    }
    return 0;
}