HDU5655 CA Loves Stick （BC）

CA Loves Stick

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 262144/262144 K (Java/Others)

Total Submission(s): 1    Accepted Submission(s): 0

Problem Description

CA loves to play with sticks.
One day he receives four pieces of sticks, he wants to know these sticks can spell a quadrilateral.
(What is quadrilateral? Click here: https://en.wikipedia.org/wiki/Quadrilateral)

 

Input

First line contains T denoting the number of testcases.
T testcases follow. Each testcase contains four integers a,b,c,d in a line, denoting the length of sticks.
1≤T≤1000, 0≤a,b,c,d≤263−1

 

Output

For each testcase, if these sticks can spell a quadrilateral, output "Yes"; otherwise, output "No" (without the quotation marks).

 

Sample Input

   
   
   
   

    
    
    
    2 1 1 1 1 1 1 9 2
   
   
   
   

 

Sample Output

   
   
   
   

    
    
    
    Yes No
   
   
   
   

 

Source

BestCoder Round #78 (div.2) 

题意：给出四条边长，求是否可能组成一个四边形。

分析：就只要判断最长的那条边是不是比其他三条边之和大就行了；主要是数据坑啊！！

<span style="font-size:18px;">#include <iostream>
#include <cstdio>
#include <cstring>
#include <stack>
#include <queue>
#include <map>
#include <set>
#include <vector>
#include <cmath>
#include <algorithm>
using namespace std;
const double eps = 1e-6;
const double pi = acos(-1.0);
const int INF = 0x3f3f3f3f;
const int MOD = 1000000007;
#define ll long long
#define CL(a,b) memset(a,b,sizeof(a))
#define lson (i<<1)
#define rson ((i<<1)|1)
#define MAXN 100010

int main()
{
    ll n;
    ll a[4];
    cin>>n;
    while(n--)
    {
        cin>>a[0]>>a[1]>>a[2]>>a[3];
        sort(a, a+4);
        if(a[0] == 0){cout<<"No"<<endl; continue;}
        if(a[2]>(a[3]-a[0]) || a[2]>((a[3]-a[0])-a[1]))
            cout<<"Yes"<<endl;
        else cout<<"No"<<endl;
    }
    return 0;
}</span>