Follow up for "Find Minimum in Rotated Sorted Array":
What if duplicates are allowed?Would this affect the run-time complexity? How and why?
Suppose a sorted array is rotated at some pivot unknown to you beforehand.
(i.e., 0 1 2 4 5 6 7
might become 4 5 6 7 0 1 2
).
Find the minimum element.
The array may contain duplicates.
public class Solution { public int findMin(int[] num) { if(num.length==0){ return Integer.MAX_VALUE; } int left = 0,right = num.length-1; while(left<right){ if(num[left]<num[right]) return num[left]; int mid = (left+right)/2; if(num[mid]>num[right]){ if(mid==left) left = mid++; left = mid; }else if(num[mid]==num[right]){ if(num[mid]==num[left]){ return Math.min(findMin(Arrays.copyOfRange(num, left, mid)), findMin(Arrays.copyOfRange(num, mid+1,right+1))); }else if(num[mid]>num[left]){ return num[left]; }else { right = mid; } }else{ right = mid; } } return num[left]; } }
public class Solution { public int findMin(int[] num) { assert num.length>0; int left = 0,right = num.length-1; while(left<right&&num[left]>=num[right]){ int mid = (left+right)/2; if(num[mid]>num[right]){ left = mid+1; }else if(num[mid]<num[right]){ right = mid; }else{ // left++; } } return num[left]; } }