Hangman Judge |
In ``Hangman Judge,'' you are to write a program that judges a series of Hangman games. Foreach game, the answer to the puzzle is given as well as the guesses. Rules are the same as theclassic game of hangman, and are given as follows:
______ | | | O | /|\ | | | / \ __|_ | |______ |_________|
Your task as the ``Hangman Judge'' is to determine, for each game, whether the contestant wins,loses, or fails to finish a game.
Your program will be given a series of inputs regarding the statusof a game. All input will be in lower case. The first line of each section will contain a number toindicate which round of the game is being played; the next line will be the solution to the puzzle;the last line is a sequence of the guesses made by the contestant. A round number of-1 would indicate the end of all games (and input).
The output of your program is to indicate which round of the game the contestant is currently playing as well as the result of the game. There are three possible results:
You win. You lose. You chickened out.
1 cheese chese 2 cheese abcdefg 3 cheese abcdefgij -1
Round 1 You win. Round 2 You chickened out. Round 3 You lose.
一个游戏,计算机给出一个字串让你猜,你每次可以猜一个字母。如果单词里有那个字母,所有该字母会显示出来;如果没有那个字母,则计算机会在一副“刽子手”画上填一笔。这幅画一共需要七笔就能完成,因此你最多只能错6次。注意,一个已经猜过的字母也算错。
题目并没有难度,但码完后还是出现了bug,结合书本后,发现是考虑错了一种情况,即当计算机给出的字串全部猜对后,即可停止,并赢得比赛。改完后,提交AC。#include <stdio.h> #include <string.h> char s1[1000],s2[1000]; int left,chance; int win,lose; void guess(char ch) { int p,i; p=1; for (i=0;i<strlen(s1);i++) if (ch==s1[i]) { s1[i]=' '; p=0; left--; } if (p==1) chance++; if (chance>6) lose=1; if (left==0) win=1; } int main() { int len1,k,i; while (scanf("%d",&k)==1 && k!=-1) { scanf("%s",s1); scanf("%s",s2); chance=0; win=lose=0; printf("Round %d\n",k); left=strlen(s1); len1=strlen(s2); for (i=0;i<len1;i++) { guess(s2[i]); if (win || lose) break; } if (lose) printf("You lose.\n"); else if (win) printf("You win.\n"); else printf("You chickened out.\n"); //printf("%d %d\n",left,chance); //printf("%s\n",s1); memset(s1,0,sizeof(s1)); } return 0; }