Bone Collector

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C - Bone Collector
Time Limit:1000MS Memory Limit:32768KB 64bit IO Format:%I64d & %I64u

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Practice

HDU 2602

Description

Many years ago , in Teddy’s hometown there was a man who was called “Bone Collector”. This man like to collect varies of bones , such as dog’s , cow’s , also he went to the grave …
The bone collector had a big bag with a volume of V ,and along his trip of collecting there are a lot of bones , obviously , different bone has different value and different volume, now given the each bone’s value along his trip , can you calculate out the maximum of the total value the bone collector can get ?

Input

The first line contain a integer T , the number of cases.
Followed by T cases , each case three lines , the first line contain two integer N , V, (N <= 1000 , V <= 1000 )representing the number of bones and the volume of his bag. And the second line contain N integers representing the value of each bone. The third line contain N integers representing the volume of each bone.

Output

One integer per line representing the maximum of the total value (this number will be less than 2 31).

Sample Input

1
5 10
1 2 3 4 5
5 4 3 2 1

Sample Output

14

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Server Time: 2016-05-08 20:46:21

#include<iostream>
#include<algorithm>
#include<cstring>
using namespace std;
int OneZorePack(int value[],int volume[],int n,int m)
{
    int f[100000]={0};
    for(int i=0;i<n;i++)//开始老是Wa，不知道为什么，但是在网上搜了一下题，然后改了一下i从0开始就对了，不知道为什么？
    {
        for(int j=m;j>=volume[i];j--)
        {
            f[j]=max(f[j-volume[i]]+value[i],f[j]);
        }
    }
    return f[m];
}
int main()
{
    int t;
    cin>>t;
    int n,m;
    int value[1000+5],volume[1000+5];
    while(t--)
    {
        cin>>n>>m;
        for(int i=0;i<n;i++)
            cin>>value[i];
        for(int i=0;i<n;i++)
            cin>>volume[i];
        cout<<OneZorePack(value,volume,n,m)<<endl;
    }
    return 0;
}