生产者消费者问题--多线程 wait() notify()

public class Consume_Produce {
public static void main(String[] args ){
 Bullet b=new Bullet();
 Produce p=new Produce(b);
 Consume c=new Consume(b);
 Thread t1=new Thread(p);
 Thread t2=new Thread(c);
 t1.start();
 t2.start();
 
}
}

 

 

class Bread{
 public int id;
 public Bread(int id){this.id=id;}
}

 

 

class Bullet {
 Bread b[]=new Bread[15];
 public int index=0;//bread的id
 
 public synchronized void produceBread(){
  while(index==15){                         //l篮子的容量是15，当达到15个面包时 生产线程wait
   try{this.wait();
   }catch(InterruptedException e)
   {e.printStackTrace();}
  }
  this.notify();                                 //唤醒别的线程
  b[index]=new Bread(index);
  index++;
  System.out.println("produce-----"+index);
 }
 
 public synchronized Bread consumeBread(){
  while(index==0){                          //当篮子里面没有面包时，消费线程wait()
   try{this.wait();
   }catch(InterruptedException e)
   {e.printStackTrace();}
  }
  this.notify();                                     //唤醒别的线程
  System.out.println("consume-----"+index);
  index--;
  return b[index];
  
 }
}

 

class Produce implements Runnable{   //这是一个生产线程
 Bullet b=null;
 public Produce(Bullet b){this.b=b;}
 public void run(){
 for(int i=0;i<200;i++){ 
  b.produceBread();}
 }
}

 

 

class Consume implements Runnable{ //这是一个消费线程
 Bullet b=null;
 public Consume(Bullet b){this.b=b;}
 public void run(){
  for(int i=0;i<200;i++){ b.consumeBread();}
 }
}