u Calculate e

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 34902    Accepted Submission(s): 15711

Problem Description

A simple mathematical formula for e is



where n is allowed to go to infinity. This can actually yield very accurate approximations of e using relatively small values of n.

 

Output

Output the approximations of e generated by the above formula for the values of n from 0 to 9. The beginning of your output should appear similar to that shown below.

 

Sample Output

   
   
   
   

    
    
    
    n e - ----------- 0 1 1 2 2 2.5 3 2.666666667 4 2.708333333
   
   
   
   

#include<stdio.h>

//#include<stdlib.h>
int f(int x)
{
   int l;
   if(x==0||x==1)
   l=1;
   else l=f(x-1)*x;
   return l; 
    }
main()
{
   int i,j;
   double w;
    printf("n e\n- -----------\n0 1\n1 2\n2 2.5\n");
    w=2.5;
    for(i=3;i<=9;i++)
  {  w=w+1.0/f(i);
    printf("%d %.9lf\n",i,w);
    }
//system("pause");
return 0;
}