1108. Finding Average

1108. Finding Average (20)

时间限制

400 ms

内存限制

65536 kB

代码长度限制

16000 B

判题程序

Standard

作者

CHEN, Yue

The basic task is simple: given N real numbers, you are supposed to calculate their average. But what makes it complicated is that some of the input numbers might not be legal. A "legal" input is a real number in [-1000, 1000] and is accurate up to no more than 2 decimal places. When you calculate the average, those illegal numbers must not be counted in.

Input Specification:

Each input file contains one test case. For each case, the first line gives a positive integer N (<=100). Then N numbers are given in the next line, separated by one space.

Output Specification:

For each illegal input number, print in a line "ERROR: X is not a legal number" where X is the input. Then finally print in a line the result: "The average of K numbers is Y" where K is the number of legal inputs and Y is their average, accurate to 2 decimal places. In case the average cannot be calculated, output "Undefined" instead of Y. In case K is only 1, output "The average of 1 number is Y" instead.

Sample Input 1:

7
5 -3.2 aaa 9999 2.3.4 7.123 2.35

Sample Output 1:

ERROR: aaa is not a legal number
ERROR: 9999 is not a legal number
ERROR: 2.3.4 is not a legal number
ERROR: 7.123 is not a legal number
The average of 3 numbers is 1.38

Sample Input 2:

2
aaa -9999

Sample Output 2:

ERROR: aaa is not a legal number
ERROR: -9999 is not a legal number
The average of 0 numbers is Undefined

#include<cstdio>
#include<vector>
#include<cstring>
#include<algorithm>
using namespace std;
typedef long long LL;
const int maxn = 1e5 + 10;
char s[maxn];
int n, cnt;
double avg;

bool check()
{
  int point = strlen(s), neg = s[0] == '-';
  for (int i = 0; s[i]; i++)
  {
    if ((s[i]< '0' || s[i] > '9') && s[i] != '.'&&s[i] != '-') return false;
    if (s[i] == '-' && i) return false;
    if (s[i] == '.') { if (s[point] || point - i > 3) return false; point = i; }
    //数据中没有".","-","-."这样的数据，且"1."和".1"是合法的。
  }
  double L = 0, R = 0;
  for (int i = neg; i < point; i++) L = L * 10 + s[i] - '0';
  for (int i = strlen(s) - 1; i>point; i--) R = (R + s[i] - '0') / 10;
  if (L + R > 1000.0) return false;
  avg += (neg ? -1 : 1) * (L + R);
  return true;
}

int main()
{
  scanf("%d", &n);
  while (n--)
  {
    scanf("%s", s);
    if (check()) cnt++; else printf("ERROR: %s is not a legal number\n", s);
  }
  if (!cnt) printf("The average of 0 numbers is Undefined\n");
  else printf("The average of %d number%s is %.2lf", cnt, cnt == 1 ? "" : "s", avg / cnt);
  return 0;
}