fastjson学习


1、Object转string

String ss = JSON.toJSONStirng(Object)

2、String类型的dto字符串转换成object类型dto

<span style="white-space:pre">	</span>MethodAttrDto mad = new MethodAttrDto();
        mad = JSONObject.parseObject(methodAttrString,MethodAttrDto.class);
methodAttrString类似于:{"detailId":66,"methodDesc":"","methodName":"","methodTopic":"","priotity":"1","url":"teyryry"}这种形式



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